All categories

3 years ago

Please help I will give brainly

Mathematics

2 answers:

Volgvan3 years ago

5 0

Answer:

Step-by-step explanation:

BC you need to add upall of them then devide by 1/4 and then oyu have your answer

Aleonysh [2.5K]3 years ago

5 0

It’s 30 1/4 inch cubes so it’s 30in^3

You might be interested in

Which answer shows the equation y-x=5 written in slope intercept form

Mekhanik [1.2K]

Slope intercept form is y=mx+b so the answer is y=x+5

3 0

3 years ago

Read 2 more answers

The house number if two adjacent homes are two consecutive even numbers. If their sum is 406, find the house numbers.

USPshnik [31]

Answer: follow my Instagram rihannah0423

Step-by-step explanation: PERIODT!!!!

5 0

4 years ago

Write the standard form of the equation of the line passing through (0, 1) and parallel to x = 4.

Savatey [412]

Answer:

x=0

Step-by-step explanation:

The line x=4 is a vertical line through the x-axis at 4. A line parallel to it will also be a line through the x-axis. It has the form x=a where a is the x-coordinates of any points on the line. Since the line crosses through (0,1), the equation is x=0.

5 0

3 years ago

Anna has twice as many video games as Kyle. Maurice has 5 more video games than Anna. The total number of video games is less th

NNADVOKAT [17]

Answer:

She has 17 video games. (Possible answer.) Hope this helps!

Step-by-step explanation:

$2x+5$

-5. -5

$2x$

2. 2

$X$

or 17 since it is less than 17.2

5 0

2 years ago

Read 2 more answers

A small airline overbooks flights on the assumption that several passengers will not show up. Suppose that the probability that

olchik [2.2K]

We have 22 tickets sold, and 20 seats. This means that at least 2 passengers must not show up (otherwise, at least 21 passengers will be present, and there wouldn't be space for them).

Considering each passenger as independent, you can think of this experiment. Suppose you toss a coin for each passenger. If the coin lands on heads, the passenger shows up. If it lands on tails, the passenger doesn't show up.

But the coin is unfair: it has a 0.91 probability of landing on heads, and thus 0.09 probability of landing on tails.

This implies that the probability of having exactly $k$ tails is

$\binom{22}{k} \cdot 0.09^k \cdot 0.91^{22-k}$

We already concluded that at least two passengers must not show up. So, if our coins lands on tails less than twice, we've lost. So, the losing probability is

$\displaystyle\binom{22}{0}\cdot 0.09^0 \cdot 0.91^{22} + \binom{22}{1}\cdot 0.09^1 \cdot 0.91^{21} \approx 0.39$

Finally, remember the rule to negate events:

$P(E) = 1-P(\lnot E)$

So, if we lose with probability 0.39, we win with probability

$1-0.39 = 0.61$

6 0

3 years ago