Answer:
A and C
Step-by-step explanation:
Answer:
464 grams.
Step-by-step explanation:
Amount of substance:
The amount of substance after t years is given by an equation in the following format:

In which A(0) is the initial amount and r is the decay rate, as a decimal.
Co-60 has a half life of 5.3 years.
This means that:

We use this to find r. So



![\sqrt[5.3]{(1-r)^{5.3}} = \sqrt[5.3]{0.5}](https://tex.z-dn.net/?f=%5Csqrt%5B5.3%5D%7B%281-r%29%5E%7B5.3%7D%7D%20%3D%20%5Csqrt%5B5.3%5D%7B0.5%7D)


So

If a pellet that has been in storage for 26.5 years contains 14.5g of Co-60, how much of this radioisotope was present when the pellet was put in storage?
We have that
, and use this to find A(0). So



[tex]A(0) = 464[tex]
464 grams.
Answer:
12
Step-by-step explanation:
this is very simple. since the angles are opposite the intersection of two lines, you know they must be equal.
therefore:
97 = 8t +1
solve for t:
t = 12
Answer:
x = 11
Step-by-step explanation:
x + 5 = 2(x - 3)
x + 5 = 2x - 6
(x - x) + 5 = (2x - x) - 6
5 = x - 6
5 + 6 = x (- 6 + 6)
x = 11
Step-by-step explanation:
6x - x² = k
=> x² - 6x + k = 0,
For there to be at least 1 real solution,
The discriminant b² - 4ac must be at least 0.
We have (-6)² - 4(1)(k) >= 0.
Therefore 36 - 4k >= 0, k <= 9.
Hence the largest value of k is 9.