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VikaD [51]
3 years ago
8

Which of the following are possible values for x?

Mathematics
1 answer:
Natali5045456 [20]3 years ago
4 0

Answer:

The answer is only c) x=5

Step-by-step explanation:

|x| means that this is an absolute value. If the number is a negative, removing the value bars will make it a positive again. Positives stay positives. So the only answer greater than value of 2 is 5.

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Solve the following:<br> a.) X^2 - 2x – 24 = 0<br><br> b.) x^2 - 11x + 18 =0
wolverine [178]

Answer:

The answer for the first equation is,

X = 6, -4

The answer for second equation is,

X = 9,2

7 0
3 years ago
Read 2 more answers
I need this answered Fast if possible. A car is traveling on a small highway and is either going 55 miles per hour or 35 miles
Alex787 [66]

a. It spends about 2.045 hours going 55 miles per hour

b. It spends 1 hour going 35 miles per hour

c. The trip would take about 3.64 hours

Step-by-step explanation:

A car is traveling on a small highway and is either going 55 miles per hour or 35 miles  per hour, depending on the speed limits, until it reaches its destination 200 miles  away

  • x represents the amount of time in hours that the car is going 55 miles per  hour
  • y represents the amount of time in hours that the car is going 35 miles per hour
  • The equation  that describing the relationship is 55x + 35y = 200

We need to find:

a. How long does it  spend going 55 miles per hour, if the car spends 2.5 hours going 35 miles per hour on the trip

∵ 55x + 35y = 200

∵ The car spends 2.5 hours going 35 miles per hour on the trip

∵ y represents the amount of time that the car going 35 mi./h

∴ y = 2.5

- Substitute the value of y in the equation to find the value of x

∴ 55x + 35(2.5) = 200

∴ 55x + 87.5 = 200

- Subtract 87.5 from both sides

∴ 55x = 112.5

- Divide both sides by 55

∴ x = 2.045 hours

It spends about 2.045 hours going 55 miles per hour

b.how long does it  spend going 35 miles per hour, if the car spends 3 hours going 55 miles per hour on the trip

∵ 55x + 35y = 200

∵ The car spends 3 hours going 55 miles per hour on the trip

∵ x represents the amount of time that the car going 55 mi./h

∴ x = 3

- Substitute the value of y in the equation to find the value of x

∴ 55(3) + 35y = 200

∴ 165 + 35y = 200

- Subtract 165 from both sides

∴ 35y = 35

- Divide both sides by 35

∴ y = 1 hour

It spends 1 hour going 35 miles per hour

c. How long would the trip take, if the car spends no time going 35 miles per hour

∵ 55x + 35y = 200

∵ The car spends no time going 35 miles per hour

∴ y = 0

- Substitute the value of y in the equation to find the value of x

∴ 55x + 35(0) = 200

∴ 55x  = 200

- Divide both sides by 55

∴ x = 3.63 hours

The trip would take about 3.64 hours

Learn more:

You can learn more about the equations in brainly.com/question/4097107

#LearnwithBrainly

5 0
3 years ago
Karen claps her hand and hears the echo from a distant wall 0.113 s later. How far away is the wall? The speed of sound in air i
insens350 [35]

Answer:

19.3795 m

Step-by-step explanation:

If sound travels at 343 m/s and it took Karen 0.113 s to hear the echo from the wall, the distance travelled by the sound is:

D=343\frac{m}{s} *0.113\ s\\D= 38.759\ m

Note that the distance calculated above is the distance travelled from Karen to the wall and then back from the wall to Karen. Therefore, the distance between Karen and the wall is:

d=\frac{38.759}{2}\\d=19.3795\ m

The wall is 19.3795 m away from Karen.

3 0
3 years ago
1. tan a = cot(a + 10°)
Temka [501]

Answer:

a=40+90n

Step-by-step explanation:

Use a cofunction identity on the right hand side or left hand side...

So \tan(a)=\cot(90-a).

We have the equation:

\tan(a)=\cot(a+10)

Make the above replacement:

\cot(90-a)=\cot(a+10)

Since cotangent has period 180 degrees, we can also write this as:

\cot(90-a+180n)=\cot(a+10)

So solving the following will give us a set of solutions for a:

90-a+180n=a+10

Add a on both sides:

90+180n=2a+10

Subtract 10 on both sides:

80+180n=2a

Divide both sides by 2:

40+90n=a

Symmetric property:

a=40+90n

7 0
2 years ago
Which figure shows a reflection of pre-image DEFG over the x-axis?
user100 [1]

Answer:

The second one is the right one

8 0
3 years ago
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