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IgorLugansk [536]
2 years ago
11

Please help with these questions (no links)

Mathematics
1 answer:
seraphim [82]2 years ago
3 0
If the cakes are circles,
3.14(4)2= 50.24
3.14(5)2= 78.5
78.5-50.24= 28.26

#1 is 28.26
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3 years ago
There are values of t so that sin t=.35 and cos t=.6
NISA [10]

Recall the fundamental rule of trig:

\sin^2(x)+\cos^2(x)=1 \quad\forall x \in \mathbb{R}

So, there exists an angle t such that

(0.6,0.35)=(\sin(t),\cos(t))

if and only if

\sin^2(t)+\cos^2(t)=0.6^2+0.35^2=1

Working out the numbers, we get

0.6^2+0.35^2=0.36+0.1225=0.4825\neq 1

So, there doesn't exist a number t such that

(0.6,0.35)=(\sin(t),\cos(t))

7 0
3 years ago
What is the value of x in the equation 6(x +11)= -300?
Kay [80]

Answer:

-61

Step-by-step explanation:

We use the distributive property to distribute 6 to both x and 11. This gives 6x+66=-300. Subtracting both sides by 66 gives 6x=-366. Dividing both sides gives x=-61.

8 0
3 years ago
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