The net electric field is the vector sum of the components of the electric
field produced by the two charges.
The values of the magnitude and direction of the net electric field at the origin (approximate values) are;
- 12.6 ° above the negative x–axis
<h3>How are the net electric field magnitude and direction calculated?</h3>
The possible questions based on a similar question posted online are;
(a) The net electric field at the origin.
The electric field due to charge q₁ is given as follows;
Which gives;
Which gives;
Therefore;
![\vec {E} = \left[ 21.6 \, N/C - 150 \, N/C \right] \left( \hat x \right) + \left(28.8 \, N/C \right) \left( \hat y \right)](https://tex.z-dn.net/?f=%5Cvec%20%20%7BE%7D%20%3D%20%5Cleft%5B%2021.6%20%5C%2C%20N%2FC%20-%20150%20%5C%2C%20N%2FC%20%5Cright%5D%20%5Cleft%28%20%5Chat%20x%20%5Cright%29%20%2B%20%5Cleft%2828.8%20%5C%2C%20N%2FC%20%5Cright%29%20%5Cleft%28%20%5Chat%20y%20%5Cright%29)
The magnitude of the net electric field is therefore;
E = 
≈ 131.6
- The magnitude of the net electric field at the origin is E ≈<u> 131.6 N/C</u>
(b) The direction of the net electric field at the origin.
Learn more about electric field strength here:
brainly.com/question/14743939
brainly.com/question/3591946
The average speed between t = 1.0 s and t = 4.0 s will be 2.1+0.3 which is 2.4m/s
<h3>
Velocity function </h3>
Given the equation for the position of the mouse expressed as:
The velocity of the particle is expressed as:
Given that p = 0. 40 m/s and q = -1. 10 m/s, the equation will become:
If the time is <em>t = 1.0 s, the velocity will be:</em>
Similarly if t = 4.0ssec, hence:
The average speed between t = 1.0 s and t = 4.0 s will be 2.1+0.3 which is 2.4m/s
<em>Learn more on</em><em> average speed </em><em>here: brainly.com/question/4931057</em>
Complete question
<em>A mouse runs along a baseboard in your house. The mouse's position as a function of time is given by x(t)=pt 2+qt, with p = 0.40 m/s2and q = -1.10 m/s . Determine the mouse's average speed between t = 1.0 s and t = 4.0 s. I have tried everything and the answer is not 0.40 m/s</em>
Answer:
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