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2 years ago

Pls help me with this!!!!!!!!!

Mathematics

1 answer:

docker41 [41]2 years ago

6 0

Answer:

i say it is the option A

hope this helps

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Shereen wishes to advertise her business, so she gives packs of 5 red flyers to each restaurant owner and sets of 10 blue flyers

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Step-by-step explanation:

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2 years ago

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Deon is going to watch a movie in his collection. He has 10 action movies, 5 comedies, and 8 dramas. He will randomly select one

nadezda [96]

Answer:

the probability that it is not a drama movie is 15/23

Step-by-step explanation:

To calculate the probability we have to make the number of favorable events divided the number of possible events

number of possible events = x

to calculate it we add all the movies

x = 10 + 5 + 8

x = 23

number of favorable events = y

to calculate it we subtract the drama movies from the total of movies

y = x - 8

y = 23 - 8

y = 15

now we divide 15 by 23 and we get the probability

15/23

8 0

3 years ago

Does anyone know how to do this

Scilla [17]

Answer:

$7 {x}^{2} + 28x - 35 = 0$

$7 {x}^{2} + 35x - 7x - 35 = 0$

$7x(x + 5) - 7(x + 5) = 0$

$(x + 5)(7x - 7) = 0$

$(x + 5)(x - 1) = 0$

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2 years ago

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Shirley wants to buy a skateboard for $64. She has $98 in her account. She spent $10.85 to buy stationary. She also wants to buy

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She can get 14 cookies

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2 years ago

The management of a relatively new social networking website named BooglePlus is conducting a pilot study comparing use of its o

zavuch27 [327]

Answer:

0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x

Step-by-step explanation:

Given the data in the question;

sample size n = 28

slope of the least squares regression line of y on x or sample estimate = 0.0623

standard error = 0.0224

95% confidence interval

level of significance ∝ = 1 - 95% = 1 - 0.95 = 0.05

degree of freedom df = n - 2 = 28 - 2 = 26

∴ the equation will be;

⇒ sample estimate ± ( t-test) ( standard error )

⇒ sample estimate ± ( $t_{\alpha /2, df$ ) ( standard error )

⇒ sample estimate ± ( $t_{0.05 /2, 26$ ) ( standard error )

⇒ sample estimate ± ( $t_{0.025, 26$ ) ( standard error )

{ from t table; ( $t_{0.025, 26$ ) = 2.055529 = 2.056

so we substitute

⇒ 0.0623 ± ( 2.056 )( 0.0224 )

Therefore, 0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x

5 0

2 years ago

Pls help me with this!!!!!!!!!​

Pls help me with this!!!!!!!!!