Answer:
0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.
Each minute has 60 seconds, so 
Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So
We want 
. So
In which
0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.
Answer:
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 67
Variance = 3.85
We have to find 80% confidence interval for the population variance of the weights.
Degree of freedom = 67 - 1 = 66
Level of significance = 0.2
Chi square critical value for lower tail =
Chi square critical value for upper tail =
80% confidence interval:
Putting values, we get,
Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.
Answer:
the speed s=65 mph
distance to reach d=26 miles
what is time required to reach 26 miles with a speed of 65mph , t?
distance =speed x time
time= d/s
t=26/65=0.4hrs=24minutes would be the answer
Answer:
1/600 or 0.00166666 in decimal
Step-by-step explanation:
6*10^-2=1/(6*10^2)=1/(6*100)=1/600
<span>2 the Air Slammers because they are the best price.
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