The ordered pair is a solution of x - y = 2 and 3y - x = 8 is (x, y) = (7, 5)
<h3><u>Solution:</u></h3>
Given two equations are:
x - y = 2 and 3y - x = 8
<em><u>To find: orderes pair i.e (x, y)</u></em>
Let us consider:
x - y = 2 ------- eqn 1
3y - x = 8 --------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "x" and "y"</u></em>
On rearranging eqn 2, we get
-x + 3y = 8 ------ eqn 3
Add eqn 1 and eqn 3
x - y = 2
-x + 3y = 8
(+) ---------------
0 + 2y = 10
2y = 10
<h3>y = 5</h3>
Therefore from eqn 1,
x - y = 2
x - 5 = 2
x = 5 + 2 = 7
<h3>x = 7</h3>
Thus the ordered pair to the given equations are (x, y) = (7, 5)
Answer:
19.5^2 + x^2 = 20^2
Step-by-step explanation:
You would use the pythagorean theorem to find the missing side length
Answer:
Step-by-step explanation:
The given equation is
To solve for , first, we need to sum 1 unit to each side of the equation.
Then, we divide the equation by 10
Finally, we subtract each side with -1
Therefore, the solution to the given equation is
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Answer:
5x - 2y= -28
Step-by-step explanation:
Since the y= mx + b format would be: y= 5/2x + 14
Standard form is: 5x - 2y= -28