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2 years ago

Help asap!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Temka [501]2 years ago

5 0

Answer: Um i think someone else from your school asked the same exact question and i literally just answered it, just click on my account to see the answer.....

Step-by-step explanation:

You might be interested in

Which triangles are right triangles?<br> Select ALL correct answers.

vredina [299]

Answer:

2 , 3 ,4

Step-by-step explanation:

to find the right triangle use the pythagorian method

A^2+B^2= C^2

5 0

2 years ago

How many pairs of whole numbers have the Sum of 12

nataly862011 [7]

Thanks for the question!

Don't forget 0 is a whole number:

0 + 12
1 + 11
2 + 10
3 + 9
4 + 8
5 + 7
6 + 6

Hope this helps!

8 0

3 years ago

(3x+4)–(2x+9)=15<br><br> Help meeeeeeeeeeeee.

melamori03 [73]

Answer:

x=30

Step-by-step explanation:

you distribute the negative to 2x and 19

3x+4-2x-19=15

then you combine like terms

x-15=15

you add 15 to both sides

x=30

4 0

3 years ago

Read 2 more answers

[HELP] For j(x) = <img src="https://tex.z-dn.net/?f=5%5Ex%5E-%5E3" id="TexFormula1" title="5^x^-^3" alt="5^x^-^3" align="absmidd

Alina [70]

The difference quotient of the function that has been presented to us will turn out to be 5.

<h3>How can I calculate the quotient of differences?</h3>

In this step, we wish to determine the difference quotient for the function that was supplied.

To begin, keep in mind that the difference quotient may be calculated by:

Lim h->0 $\frac{f(x+h)-f(x)}{h}$

Now, for the purpose of the function, we need this:

Then we will have:

$\begin{aligned}&\lim _{h \rightarrow 0} \frac{j(x+h)-j(x)}{h} \\&\lim _{h \rightarrow 0} \frac{5 *(x+h)-3-5 * x+3}{h} \\&\lim _{h \rightarrow 0} \frac{5 x+5 h-3-5 x+3}{h} \\&\lim _{h \rightarrow 0} \frac{5 h}{h}=5\end{aligned}$

j(x) = 5x - 3

Then the following will be true:

Therefore, 5 is the value of the difference quotient for j(x) is %

Read the following if you are interested in finding out more about difference quotients:

brainly.com/question/15166834

#SPJ1

6 0

11 months ago

Cesar turned in his third research report, his teacher said that he had completed 20%of the reports for the school year, how man

AleksAgata [21]

Answer:

Cesar will be doing 15 research reports during the school year.

Step-by-step explanation:

Given:

Number of research report completed = 3

Percentage of the report completed for school year = 20%

We need to find total number of research report completed during school year.

Solution:

Let the total number of research report completed during school year be 'x'.

Now we can say that;

Number of research report completed is equal to Percentage of the report completed for school year multiplied by total number of research report completed during school year and then divided by 100.

framing in equation form we get;

$3=\frac{20}{100}\times x\\\\3=0.2x$

Dividing both side by 0.2 we get;

$\frac{3}{0.2}=\frac{0.2x}{0.2}\\\\x=15$

Hence Cesar will be doing 15 research reports during the school year.

6 0

3 years ago