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Nata [24]
3 years ago
7

Let U be a square matrix such that Upper U Superscript Upper TUequalsI. Show that det Uequalsplus or minus1. Assume that Upper U

Superscript Upper TUequalsI. Since the desired result is that det Uequalsplus or minus​1, an intermediate step must be found which contains the expression det U. Which of the following can be applied to the assumption Upper U Superscript Upper TUequalsI to achieve the desired​ result? A. det ​(Upper U Superscript Upper T​U)Superscript negative 1equalsdet I B. det ​(Upper U Superscript Upper T​U)equalsI C. ​(Upper U Superscript Upper T​U)Superscript negative 1equalsISuperscript negative 1 D. det ​(Upper U Superscript Upper T​U)equalsdet I Simplify the right side of the equation found in the first step. nothing Which property can be used to simplify the left side of the equation found in the first​ step? Select all that apply.

Mathematics
1 answer:
bogdanovich [222]3 years ago
4 0

Answer:

See explaination

Step-by-step explanation:

Please kindly check attachment for the step by step solution of the given problem.

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What is the first step of the following division problem?
yanalaym [24]

Answer:

Divide 8x^3 by 2x

Step-by-step explanation:

Here, we want to identify the first step to take in the polynomial division.

When working with a polynomial division, what to do is to divide the first term of the dividend by the first term of the divisor ( the divisor is arranged in descending powers of x)

The number we want to divide is the dividend, while the number we are using to divide is the divisor.

In this case, the first term of the dividend is 8x^3 while that of the divisor is 2x

4 0
4 years ago
Read 2 more answers
What is the compound interest if $470 is invested for 9 years at 10% compounded continuously?
disa [49]

Compound interest formula

P = the principal (the initial amount)  

r=  annual

interest rate (

expressed

as a decimal)


expressed

as a decimal)

annual

interest rate (

expressed

as a decimal)  

n=

number of

interest periods  

per year  

(see the  

table below

for more information)  

t=

number of years

P is invested  

A=amount after t  

years

If investment interest rate is  

compounded monthly

, then n = 12  

If investment interest rate is  

compounded quarterly

, then n = 4  

If investment interest rate is

compounded semi-annually

, then n = 2

If investment interest rate is  

compounded annually

, then n = 1

4 0
3 years ago
Find the arc length of the given curve between the specified points.
yuradex [85]

Answer:

4.25

Step-by-step explanation:

Given:

f(x) = \frac{x^3}{12} + \frac{1}{x} \\\\Arc Length = \int\limits^a_b {\sqrt{1 + (f'(x))^2}  } \, dx \\f '(x) = \frac{x^2}{6} - \frac{1}{x^2}\\\\f'(x)^2 = (\frac{x^2}{6} - \frac{1}{x^2})^2 = \frac{x^4}{36} +  \frac{1}{x^4} - \frac{1}{3}\\\\1 + f'(x)^2 = \frac{x^4}{36} +  \frac{1}{x^4} + \frac{2}{3}\\\\\= \frac{x^8 + 36 + 12x^4}{36x^4}\\\\= \frac{(x^4 + 6)^2}{36x^4}\\\\=\sqrt{1 + f'(x)^2}  = \sqrt{ \frac{(x^4 + 6)^2}{36x^4}}\\\\= \frac{x^2}{6} + \frac{1}{x^2} \\\\

ArcLength = \int\limits^4_1 {\frac{x^2}{6} + \frac{1}{x^2}  } \, dx \\= (\frac{x^3}{18} -  \frac{1}{x})\limits^4_1\\\\= (\frac{64}{18} - \frac{1}{4}) - (\frac{1}{18} - 1)\\\\= \frac{17}{4}= 4.25

8 0
3 years ago
What Is 3 Over 4 Plus 7 Over 8 Plus 5 Over 6 ?<br><br> Please Help
sesenic [268]
First 3/4 = 18/24
        7/8 = 21/24
        5/6 = 20/24
18+21+20=59/24 
Hope this helps too!
3 0
4 years ago
Can someone help me and explain because i don’t understand.
attashe74 [19]

Answer:

y=33 degree

Step-by-step explanation:

y = 33 degree (the relation between y and 33 is they are vertically opposite angles anf verticelly opposite angles are always equal)

4 0
3 years ago
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