Answer:
12 hour 24 hour
08:05pm 20:05pm
12:01am 00:01am
Step-by-step explanation:
Let U be a square matrix such that Upper U Superscript Upper TUequalsI. Show that det Uequalsplus or minus1. Assume that Upper U
Superscript Upper TUequalsI. Since the desired result is that det Uequalsplus or minus1, an intermediate step must be found which contains the expression det U. Which of the following can be applied to the assumption Upper U Superscript Upper TUequalsI to achieve the desired result? A. det (Upper U Superscript Upper TU)Superscript negative 1equalsdet I B. det (Upper U Superscript Upper TU)equalsI C. (Upper U Superscript Upper TU)Superscript negative 1equalsISuperscript negative 1 D. det (Upper U Superscript Upper TU)equalsdet I Simplify the right side of the equation found in the first step. nothing Which property can be used to simplify the left side of the equation found in the first step? Select all that apply.
1 answer:
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Answer:
The coordinates of the vertex are (-5, 41)
Step-by-step explanation:
For a quadratic function of the form
Where a, b and c are constants and represent the coefficients of the function, then the symmetry of the parabola always passes through its vertex.
In this case we have the following parabola
And we know that its axis of symmetry is the line
Then we know that this axis of symmetry passes through the vertex of the parabola.
Therefore, the x coordinate of the vertex is -5.
To find the coordinate in y of the vertex, we substitute x = -5 in the function.
Finally, the vertices are in the point (-5, 41).