Answer:
Let U be a square matrix such that Upper U Superscript Upper TUequalsI. Show that det Uequalsplus or minus1. Assume that Upper U
Superscript Upper TUequalsI. Since the desired result is that det Uequalsplus or minus1, an intermediate step must be found which contains the expression det U. Which of the following can be applied to the assumption Upper U Superscript Upper TUequalsI to achieve the desired result? A. det (Upper U Superscript Upper TU)Superscript negative 1equalsdet I B. det (Upper U Superscript Upper TU)equalsI C. (Upper U Superscript Upper TU)Superscript negative 1equalsISuperscript negative 1 D. det (Upper U Superscript Upper TU)equalsdet I Simplify the right side of the equation found in the first step. nothing Which property can be used to simplify the left side of the equation found in the first step? Select all that apply.
1 answer:
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Hello!
First of all let's find the perimeter (circumference) of the semi circles. We can combine them to make one circle with a diameter of 4 (as we can see the side length of one semi circle is 4 cm. We now plug it into the circumference equation (
=3.14).
4(3.14)=12.56
Now we add up the side lengths of the rectangle.
4+6+4+6=20
Now we add up the length of our circle and rectangle.
20+12.56=32.56
Therefore our answer is 32.56 cm.
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Now to find the area! If we combine the two semicircles, we get a circle with a diameter of four. This means that is has a radius of two. We use the equation below to find the area of the two circles.
A=r²
First we will square our radius.
2(2)=4
Now we multiply by pi.
4(3.14)=12.56
Now we need to find the area of the rectangle.
6(4)=24
Now we add.
24+12.56=36.56.
I hope this helps!
First of all let's find the perimeter (circumference) of the semi circles. We can combine them to make one circle with a diameter of 4 (as we can see the side length of one semi circle is 4 cm. We now plug it into the circumference equation (
4(3.14)=12.56
Now we add up the side lengths of the rectangle.
4+6+4+6=20
Now we add up the length of our circle and rectangle.
20+12.56=32.56
Therefore our answer is 32.56 cm.
----------------------------------------------------------
Now to find the area! If we combine the two semicircles, we get a circle with a diameter of four. This means that is has a radius of two. We use the equation below to find the area of the two circles.
A=
First we will square our radius.
2(2)=4
Now we multiply by pi.
4(3.14)=12.56
Now we need to find the area of the rectangle.
6(4)=24
Now we add.
24+12.56=36.56.
I hope this helps!