Let U be a square matrix such that Upper U Superscript Upper TUequalsI. Show that det Uequalsplus or minus1. Assume that Upper U
Superscript Upper TUequalsI. Since the desired result is that det Uequalsplus or minus1, an intermediate step must be found which contains the expression det U. Which of the following can be applied to the assumption Upper U Superscript Upper TUequalsI to achieve the desired result? A. det (Upper U Superscript Upper TU)Superscript negative 1equalsdet I B. det (Upper U Superscript Upper TU)equalsI C. (Upper U Superscript Upper TU)Superscript negative 1equalsISuperscript negative 1 D. det (Upper U Superscript Upper TU)equalsdet I Simplify the right side of the equation found in the first step. nothing Which property can be used to simplify the left side of the equation found in the first step? Select all that apply.
1 answer:
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Answer:
b. y = −0.5x + 5.5
Step-by-step explanation:
Well first we need to find the slope of line CD.
To do that we'll use the following formula,
We'll use the points (1,1) and (3,5)
So y2 is 5 y1 is 1 so 5-1 = 4
3-1 = 2
<u>Slope = 2x</u>
If the slope of line CD is 2x we can cross out choices C and D.
Two lines that are perpendicular to each other have reciprocal slopes,
meaning is the slope of line CD is 2 then its perpendicular lines slope should be -.5.
If the perpendicular line goes through point (-1,6), the y intercept would be, 5.5.
Look at the image below ↓
<em>Thus,</em>
<em>the answer is option b. y = −0.5x + 5.5.</em>
<em>Hope this helps :)</em>
