HELPPP A GIRL OUT pleaseeee

If a quadratic equation has a real root, what do you know about the other roots of the equation? Explain.

notsponge [240]

Answer:

A Quadratic Equation can have upto 2 roots maximum. So,if one of the roots is a Real number, there are following two possibilities:

1) The other root is also a real number, but a different number

2) Its a repeated root, so the other root is the same number.

The other root cannot be a complex number as its not possible for one root to be real and other to be complex. Either no root will be complex or both will be complex roots.

Following are 3 possibilities for the roots of a quadratic equation:

2 Real and Distinct roots
2 Real and Equal roots
2 Complex roots

7 0

3 years ago

the gasoline gauge on a van initially read 1/8 full. When 15 gallons were added to the tank, the gauge read 3/4 full. how many m

nexus9112 [7]

Let x be the capacity of the tank then
3x/4-x/8 =15,
then x=24, so so far it has 3/4 *24 =18 so you need 6 gallons to fill it up

5 0

3 years ago

PLEASE HELP, ITS TIMED SO HURRY PLEASE>>>>>>>

Olegator [25]

Answer:

The answer is noncollinear

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

If a basketball has a volume of 12,114.7 cm3, what is the distance across of a basketball

kirza4 [7]

All we need to do is start with the volume formula. Then, input the volume and solve the equation for the radius. And double it to get the diameter.

V = (4/3)pi(r^3)
12114.7 = (4/3)pi(r^3) Divide both sides by (4/3) and pi
2893.64 = r^3 Take the cube root of both sides
14.25 = r

So the diameter is about 28.5 cm (14.25 x 2 = 28.5)

4 0

3 years ago

In a clinical study, volunteers are tested for a gene that has been found to increase the risk for a disease. The probability th

MrRa [10]

Answer:

a) 0.984

b) 20 people

Step-by-step explanation:

a)

If The probability that a person carries the gene is 0.1, then in a sample of 20 people, 2 should carry the gene.

Now, we want to know how many samples there are with this property.

Since we have 20 elements where 18 are alike (do not carry the gene) and 2 are alike (carry the gene), we have to compute the number of permutations of 20 elements in which 18 are alike and 2 are alike. This number is

$\frac{20!}{18!2!}=190$

In this 190 20-tuples there are only 3 where the 2 carriers of the gene are in the first 3 places, namely

(1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

where 1=carries the gene, 0=does not carry the gene.

So there are 190-3 = 187 elements in which the first 3 elements have no 2 carriers, hence the probability that 4 or more people will have to be tested until 2 of them with the gene are detected is 187/190 = 0.984 (98.4%) rounded to three decimal places.

b)

Given that the probability that a person carries the gene is 0.1, then in a sample of 20 people, 20*0.1 = 2 should carry the gene.

4 0

3 years ago