Answer:
![-7\frac{1}{2}](https://tex.z-dn.net/?f=-7%5Cfrac%7B1%7D%7B2%7D)
Step-by-step explanation:
To find the quotient, convert the mixed number to an improper fraction first
![-3\frac{1}{3}=-\frac{3*3+1}{3}=-\frac{10}{3}](https://tex.z-dn.net/?f=-3%5Cfrac%7B1%7D%7B3%7D%3D-%5Cfrac%7B3%2A3%2B1%7D%7B3%7D%3D-%5Cfrac%7B10%7D%7B3%7D)
Find the quotient now
![\frac{(-10/3)}{(4/9)}=-\frac{10*9}{4*3}\\ \\=-\frac{90}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B%28-10%2F3%29%7D%7B%284%2F9%29%7D%3D-%5Cfrac%7B10%2A9%7D%7B4%2A3%7D%5C%5C%20%5C%5C%3D-%5Cfrac%7B90%7D%7B12%7D)
Simplify
Divide by
both numerator and denominator
![=-\frac{15}{2}=-7.5](https://tex.z-dn.net/?f=%3D-%5Cfrac%7B15%7D%7B2%7D%3D-7.5)
Convert to a mixed number
![-7.5=-(7+0.5)=-(7+\frac{1}{2})=-7 \frac{1}{2}](https://tex.z-dn.net/?f=-7.5%3D-%287%2B0.5%29%3D-%287%2B%5Cfrac%7B1%7D%7B2%7D%29%3D-7%20%5Cfrac%7B1%7D%7B2%7D)
Answer:
<em>The answer is Hence Proved</em>
Step-by-step explanation:
Given that CB║ED , CB ≅ ED
To prove Δ CBF ≅ Δ EDF
This means that the length of CB is equal to ED
As CB║ED The following conditions satisfies when a transversal cut
two parallel lines
- ∠ EDF = ∠ FBC ( Alternate interior points )
- ∠ DEF = ∠ FCB ( Alternate interior points )
∴ Δ CBF ≅ Δ EDF ( By ASA criterion)
The Δ CBF is congruent to Δ EDF By ASA criterion .
<em> Hence proved </em>
Answer:
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Step-by-step explanation:
12 would be your anwer
8, 7, undefined, 6*sqrt *2