All categories

3 years ago

Geometry math question no Guessing and Please show work thank you

Mathematics

1 answer:

Montano1993 [528]3 years ago

4 0

here triangles EBC and EKC are similar by ASA rule.

So angle BEC = angle KEC

7p+7=37-3p

adding 3p to both sides

7p+3p=37-7

10p=30

dividing both sides by 10

p=3

Answer is B. p=3

You might be interested in

Given: Point B is the midpoint of segment AC and

Feliz [49]

Answer:

Substitution

Step-by-step explanation:

5 0

3 years ago

Leg a is 15. leg b is 8, what is c?<br><br>

cricket20 [7]

Answer:

a²+b²=c² so you take 15² =225. then you take 8²=64 then you add 225+64=289. Then you find the √289 That equals 17

C=17

4 0

2 years ago

Read 2 more answers

Suppose that x = 2+2t and y = t - 21. If x = 8, what is y?

kvasek [131]

Answer:

$y=-18$

Step-by-step explanation:

So we know that:

$x=2+2t\text{ and}\\y=t-21$

And we want to figure out the value of y when x is 8.

So first, substitute 8 into the first equation:

$8=2+2t$

Solve for t. Subtract 2 from both sides:

$6=2t$

Divide both sides by 2:

$t=3$

Now, substitute this into the second equation for t:

$y=(3)-21$

Subtract:

$y=-18$

So, the value of y is -18.

And we're done!

8 0

4 years ago

A business analyst makes $20 an hour for the first 42 hours he works during a week and $28 an hour for each hour worked over 42

Natasha_Volkova [10]

The piecewise function for this should be $f(x) \left \{ {{y = 20x, x < 42} \atop {y = 28x + 840, x > 42}} \right.$ .

We can find the first equation simply. He gets 20 every hour up to 42 hours. Therefore, the function gives us our first equation of y = 20x when x < 42.

The second one, we must know what the base amount he would make before starting to make 28 an hour. The 28 an hour would be 28x, but he would have already made 840 before hand. Which we can determine by multiplying the base of 42 hrs by 20.

42 * 20 = 840.

3 0

3 years ago

Read 2 more answers

I keep on getting the wrong answer

Anon25 [30]

1) Area = (b*h)/2 = (9*5)/2 = 45/2 = 22.5 (Letter A)

2) Area = b*h = 8*14 = 112 (Letter D)

3) Surface area of a prism is SA=2B+ph (B = area of the base, p = perimeter of the base, h = height)

B = 15 * 5 = 75 cm^2

p = 15 + 5 = 20 cm

SA = 2*75 + 20*7 = 150 + 140 = 290 (G)

4) V = (B*H*L)/2 = (15*7*5)/2 = 525/2 = 262.5 cm^3 (G)

5) V = 9^3 = 81 cm^3 worth of wrapping (A)

6) V = (B*H*L)/2 = (13*6*8)/2 = 312 cube feet (J)

It gave me ADGGAJ. I don't know if this is right, but I atleast tried to do something, right?

5 0

2 years ago

Read 2 more answers