2^2x=5^x−1
Take the log pf both sides:
ln(2^2x) = ln(5^x-1)
Expand the logs by pulling the exponents out:
2xln(2) = (x-1)ln(5)
Simpligy the right side:
2xln(2) = ln(5)x - ln(5)
Now solve for x:
Subtract ln(5)x from both sides:
2xln(2) - ln(5)x = -ln(5)
Factor x out of 2xln(2)-ln(5)x
x(2ln(2) - ln(5)) = -ln(5)
Divide both sides by (2ln(2) - ln(5))
X = - ln(5) / (2ln(2) - ln(5))
The correct answer is a Trapezoid.
First, I drew and labeled the points on a graph. When these points are connected, you can see that the space between DA and CB is not equal, meaning that the trapezoid is not isosceles.
Answer:
RT=6.5
PV=7.3
Step-by-step explanation:
Answer:
t = 25.1seconds
Step-by-step explanation:
X(t)= 16cos75°t
Y(t)= 6 + (Vosin75°t - 16t^2)
Converting 78 yards to feet :
1 yard = 3 feet
78feet =?
78×3=234 feet
Y(t)= number of feet above the ground at t seconds
VoCos75° t = 234
t = 234/(VoCos75°)
At this time,4 = y(234/VoCos75°)
4 = 6 + VoSin75°(234/VoCos75) - 16(234/VoCos75°)^2
Vo= 140.66ft/s
Time,t= 234/(140.66× Cos75°)
t = 25.087seconds
t= 25.1 seconds (1 decimal place)
