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Stolb23 [73]
2 years ago
15

Find All Real Square Roots Of 144

Mathematics
1 answer:
HACTEHA [7]2 years ago
6 0

Answer:

plus or minus 12

hope that help

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A sign standing 6 feet tall is situated 18 feet away from a flag pole. at a certain time of day the sign's shadow is 3 feet long
alexdok [17]
Observe attached picture.

On picture we have:
A = height of flagpole = x ft
B = length of flagpole's shadow = 24 ft
C = height of sign = 6 ft
D = length of sign's shadow = 3 ft

When we draw a picture representing this problem we can also add another line marked in red. This way we can see that we have two right-angle triangles. We can see that both have same angle marked with α.

We can apply trigonometry rules to find height of flagpole.

From small triangle containing sign we can find tangens function:
tan \alpha = \frac{C}{D}
Similarly we can do for large triangle containing flagpole:
tan \alpha = \frac{A}{B}

We see that these two equations have same left sides. This means that their right sides must also be same:
\frac{C}{D} = \frac{A}{B}
We can solve for A:
CB=AD \\ A= \frac{CB}{D}  \\ A= \frac{6*24}{3}  \\ A=48 ft

Height of flagpole is 48 feet.

8 0
3 years ago
Jason wants to plant 66 carrot seeds and 44 onion bulbs. He would like to plant them so
dexar [7]

The greatest number of plants he can have in each row is 22

He would have 3 rows of carrots

He would have 2 rows of onions

<h3>Greatest Common Factor</h3>

From the question, we are to determine the greatest number of plants he can have in each row

From the given information,

Jason wants to plant 66 carrot seeds and 44 onion bulbs

The greatest number of plants he can have in each row is the greatest common factor of 66 and 44

Factors of 66: 1, 2, 3, 6, 11, 22, 33, and 66

Factors of 44:  1, 2, 4, 11, 22 and 44

The greatest common factor of 66 and 44 is 22

Thus,

The greatest number of plants he can have in each row is 22

He would have 66/22 rows of carrots

66/22 = 3

Thus,

He would have 3 rows of carrots

He would have 44/22 rows of onions

44/22 = 2

Hence, he would have 2 rows of onions

Learn more on Greatest Common Factors here: brainly.com/question/5535901

#SPJ1

3 0
1 year ago
2. What is the probability of spinning an A on the first spinner and an odd number
pychu [463]

Answer: <em>1/10</em>

Step-by-step explanation: These two events are independent, meaning the outcome of the first event doesn't affect the outcome of the second.

To find the probability of independent events, first, find the

probability of each event, then multiplies the probabilities.

The probability of spinning an A on the first spinner is 1/5

since there is 1 favorable outcome and 5 total outcomes.

The probability of spinning an odd number on the second spinner

is 3/6 which simplifies to 1/2 since there are 3 favorable outcomes,

spinning a 1, 3, or another 3 since these are odd numbers.

So now we have 1/5 × 1/2 and when multiplying fractions,

we multiply across the numerators and denominators to get 1/10.

So the probability of spinning an A, then an odd number is 1/10.

5 0
2 years ago
Find the length of diagonal XU in the hexagon below. Round your solution to 2 decimal points
SpyIntel [72]

Answer:

The length of diagonal XU is 6.40 units

Step-by-step explanation:

* Lets explain how to find the distance between two points

- The rule of the distance between two points (x_{1},y_{1})

 and (x_{2},y_{2}) is:

 d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

* Lets solve the problem

-From the attached figure:

- The coordinates of the vertex X are (2 , 2)

- The coordinates of the vertex U are (-2 , 7)

∴ The point (x_{1},y_{1}) = (2 , 2)

∴ The point (x_{2},y_{2}) = (-2 , 7)

∴ x_{1}=2,x_{2}=-2

∴  y_{1}=2,y_{2}=7

∵ d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

∴ d=\sqrt{(-2-2)^{2}+(7-2)^{2}}=\sqrt{(-4)^{2}+(5)^{2}}=\sqrt{16+25}=\sqrt{41}

∵ \sqrt{41}=6.403124

∴ d = 6.40

* The length of diagonal XU is 6.40 units

6 0
2 years ago
Plane RTX and plane TUX intersect at what figure
Alina [70]

Answer:

Line TX or XT

Step-by-step explanation:

Planes always intersect in a line.

8 0
3 years ago
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