Question

( 2 + 3 ) ^-1 x ( 2 ^-1 + 2^-1 )

Answer 1

Answer:

Step-by-step explanation:

$\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\la\la\la\la\ddddddddddddddddddddddddddddddddcleverdddddd\ffffffffffffffffffffffffffffffffffffffff\pppppppppppppppppppppppppppppppppppp\ddddddddddddddddddd\displaystyle\ \Large \boxed{ \boxed{\boldsymbol{Rule : a^{-1}=\frac{1}{a} }}} \\\\\\\\ (2+3)^{-1} \times (2^{-1}+2^{-1}) = \\\\1)\ (2+3)^{-1}=5^{-1}=\frac{1}{5} \\\\2)\ 2^{-1}+2^{-1}=\frac{1}{2} +\frac{1}{2} } =1 \\\\3)\ \frac{1}{5} \cdot 1=\boxed{\frac{1}{5} }$

Answer 2

Answer:

$\left(2+3\right)^{-1}\left\times(2^{-1}+2^{-1}\right)$

$=\frac{1}{\left(2+3\right)}\left(2^{-1}+2^{-1}\right)$

Add 2+3=5

$=\frac{1}{5}\left(2^{-1}+2^{-1}\right)$

2^-1+2^-1=2^0

$=2^0\cdot \frac{1}{5}$

$=1\cdot \frac{1}{5}$

$=\frac{1}{5}$

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