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meriva
2 years ago
14

Solve the inequality 9/2 + v > 7/5

Mathematics
1 answer:
statuscvo [17]2 years ago
4 0

Answer:

the answer is -31/20

Step-by-step explanation:

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What's the slope-intercept form that passes through the points (0, -1) and (1, 5)?
Rzqust [24]

Answer:

<h2>         y = 6x - 1</h2>

Step-by-step explanation:

\bold{slope\, (m)=\dfrac{change\ in\ Y}{change\ in\ X}=\dfrac{y_2-y_1}{x_2-x_1}}

(0, -1)    ⇒     x₁ = 0,  y₁ = -1

(1, 5)     ⇒     x₂ = 1,  y₂ = 5

So the slope:

                     \bold{m=\dfrac{5+1}{1-0}=\dfrac{6}{1}=6}

The slope-intercept form of the equation of line is y = mx + b, where m is the slope and b is the y-intercept of the line.

(0, -1)    ⇒     x₀ = 0,  y₀ = -1      ⇒   b = -1

Therefore:

                 y = 6x - 1          ←  the slope-intercept form of the equation

5 0
3 years ago
HELP ME ASAP ILL GIVE YOU BRAINLIEST!
N76 [4]

Answer:

7.  5280 feet

8. 700 meters.

9.         in.          ft.          yd.  

    A.   36          3            1

    B.   66         5.5        1.834

    C.   90         7.5        2.5                

6 0
3 years ago
-3(4x+3)+4(6x+1)=43 what is the answer
kifflom [539]

Answer:

4

Step-by-step explanation:

-3(4x +3)+4(6x +1)=43

-12x-9 +24x +4 =43

12x - 5=43

12x=43 +5

12x=48

x=48 :12

x=4

6 0
3 years ago
Read 2 more answers
Alan weighs 3 pounds more than twice what Dylan weighs. Write an expression o represent Alan’s weight in terms of Dylan’s weight
IgorLugansk [536]

Answer:

2x+3

Step-by-step explanation:

2x+3=Alan's Weight

2x= Dylan's weight times two

+3= the plus three more pounds

Which then equals Alan's weight.

4 0
3 years ago
Write the quadrants where the following points will lie. (a) (-20,13), (b) (-12, -8 ).​
frozen [14]

Answer:

(-20,\, 13) would be in the second quadrant of the cartesian plane.

(-12,\, -8) would be in the third quadrant of the cartesian plane.

Step-by-step explanation:

The horizontal and vertical axes of the cartesian plane divides the plane into four quadrants. By convention, these quadrants are numbered counterclockwise starting from the quadrant on the top right:

\begin{array}{c|c}\text{Second Quadrant} & \text{First Quadrant} \\ \cline{1-2}\\[-1em] \text{Third Quadrant} & \text{Fourth Quadrant}\end{array}.

  • Top-left: first quadrant.
  • Top-right: second quadrant.
  • Bottom-left: third quadrant.
  • Bottom-right: fourth quadrant.
  • Points on either axes (where at least one of the coordinates is 0) are not in any of the four quadrants.

The x-coordinate of the first point, (-20,\, 13), is x = -20, which is negative. Thus, this point would be to the left of the vertical axis.

Since the y-coordinate of this point, y = 13, is positive, this point would be above the horizontal axis.

Thus, the point (-20,\, 13) would be in the quadrant on the top-left corner of the cartesian plane. Therefore, this point would be in the second quadrant of the plane.

The second point (-12,\, -8) would also be to the left of the vertical axis since the x-coordinate of this point, x = -12, is negative.

This point would be below the horizontal axis since the y-coordinate of this point y = -8 is negative.

Thus, the point (-12,\, -8) would be in the quadrant on the lower-left corner of the cartesian plane. This point would be thus be in the third quadrant of the plane.

4 0
3 years ago
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