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3 years ago

Is this a polygon? Yes or no

Mathematics

2 answers:

Alja [10]3 years ago

8 0

A polygon should have straight lines so the answer is no

katovenus [111]3 years ago

5 0

Answer: No

Step-by-step explanation:

You might be interested in

Convert 0.33333...in to a fraction

erik [133]

Step-by-step explanation:

Let x = 0.3333333...

Then 10x = 3.3333333....

We have 9x = 3, so x = 3/9 or 1/3.

6 0

3 years ago

Which option summarizes what gave Chandra Gupta I power

mars1129 [50]

Answer:

Chandra Gupta I, King of India reigned from 320 to about 330 CE and founder of the Gupta empire. He was the grandson of Sri Gupta, the first known leader of the Gupta line. Chandra Gupta I, whose first life is unknown, became the local chief of the kingdom of Magadha parts of the modern state of Bihar.

Step-by-step explanation:

6 0

3 years ago

Determine the angle at the centre of a circle with radius 6.0 cm for an arc length of 8.0 cm.

sveta [45]

Answer:

Third option.

Step-by-step explanation:

You need to remember that the formula used to calculate the arc lenght is:

$arc\ length=r C$

Where "r" is the radius and "C" is the central angle in radians.

You need to solve for "C":

$C=\frac{arc\ length}{r}$

You know the radius and the arc lenght, therefore, you can substitute values to calculate the central angle in radians. Therefore, this is:

$C=\frac{8.0cm}{6.0cm}$

$C=\frac{4}{3}radians$

4 0

3 years ago

Many high school students take the AP tests in different subject areas. In 2007, of the 144,796 students who took the biology ex

Nataly [62]

Answer:

$(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942$

$(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978$

And the 90% confidence interval would be given (0.0942;0.09978).

We are confident at 90% that the difference between the two proportions is between $0.0942 \leq p_A -p_B \leq 0.09978$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion female for Biology

$\hat p_A =\frac{84199}{144796}=0.582$ represent the estimated proportion female for biology

$n_A=144796$ is the sample size for A

$p_B$ represent the real population proportion female for calculus AB

$\hat p_B =\frac{102598}{211693}=0.485$ represent the estimated proportion female for Calculus AB

$n_B=211693$ is the sample size required for B

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942$

$(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978$

And the 90% confidence interval would be given (0.0942;0.09978).

We are confident at 90% that the difference between the two proportions is between $0.0942 \leq p_A -p_B \leq 0.09978$

5 0

3 years ago

The endpoints of are E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of ?

Masteriza [31]

Answer:

$(\frac{x_e+x_f}{2} , \frac{y_e+y_f}{2})$

Step-by-step explanation:

the coordinates of midpoint is average of x value of endpoints and average of y value of endpoints

8 0

3 years ago