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3 years ago

7

Need help pls Need it

1 answer:

madreJ [45]3 years ago

7 0

B
hope this helps!!!!!

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What is the sum of a geometric sequence 1,3,9,... if there are 14 terms

Maksim231197 [3]

1, 3, 9, 27, 81, 243, 729, 2187, 6561, 19683, 59049, 177147, 531441, 1594323.
If this is the proper sequence pattern, we add up all the numbers to get a sum.
The total sum is 2391457.

7 0

3 years ago

How do I divide 2x^4 + 5x^3 + x - 1 by x^2 - 2x + 1 using long division?

Elza [17]

Answer: 2x^2+ 9x +16+ 24x- 17/ x^2- 2x +1

Step-by-step explanation:

7 0

3 years ago

36, ___, ___, 32/3 is a geometric sequence, with some terms missing. First, please solve for "r", the common ratio between each

Ksju [112]

Answer: r = 2/3

Step-by-step explanation:

In a geometric sequence, the consecutive terms differ by a common ratio. The formula for determining the nth term of a geometric progression is expressed as

Tn = ar^(n - 1)

Where

a represents the first term of the sequence.

r represents the common ratio.

n represents the number of terms.

From the information given,

a = 36

The 4th term is 32/3

n = 4

Therefore,

T4 = 32/3 = 36 × r^(4 - 1)

32/3 = 36 × r^3

Dividing both sides if the equation by 36, it becomes

32/3 × 1/36 = r^3

8/27 = r^3

Taking cube root of both sides of the equation, it becomes

(8/27)^1/3 = r^3 × 1/3

r = 2/3

3 0

3 years ago

Two shooters, Rodney and Philip, practice at a shooting range. They fire rounds each at separate targets. The targets are mark

Sedaia [141]

Complete Question

Answer:

a

$SE = 0.66}$

b

$-3.29 < \mu_1 - \mu_2 < -0.70$

Step-by-step explanation:

From the question we are told that

The sample size is n = 60

The first sample mean is $\= x _1 = 8$

The second sample mean is $\= x _2 = 10$

The first variance is $v_1 = 0.25$

The first variance is $v_2 = 0.55$

Given that the confidence level is 95% then the level of significance is 5% = 0.05

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the first standard deviation is

$\sigma_1 = \sqrt{v_1}$

=> $\sigma_1 = \sqrt{0.25}$

=> $\sigma_1 = 0.5$

Generally the second standard deviation is

$\sigma_2 = \sqrt{v_2}$

=> $\sigma_2 = \sqrt{0.55}$

=> $\sigma_2 = 0.742$

Generally the first standard error is

$SE_1 = \frac{\sigma_1}{\sqrt{n} }$

$SE_1 = \frac{0.5}{\sqrt{60} }$

$SE_1 = 0.06$

Generally the second standard error is

$SE_2 = \frac{\sigma_2}{\sqrt{n} }$

$SE_2 = \frac{0.742}{\sqrt{60} }$

$SE_2 = 0.09$

Generally the standard error of the difference between their mean scores is mathematically represented as

$SE = \sqrt{SE_1^2 + SE_2^2 }$

=> $SE = \sqrt{0.06^2 +0.09^2 }$

=> $SE = 0.66}$

Generally 95% confidence interval is mathematically represented as

$(\= x_1 -\= x_2) -(Z_{\frac{\alpha }{2} } * SE) < \mu_1 - \mu_2 < (\= x_1 -\= x_2) +(Z_{\frac{\alpha }{2} } * SE)$

=> $(8 -10) -(1.96 * 0.66) < \mu_1 - \mu_2 < (8-10) +(Z_{\frac{\alpha }{2} } * 0.66)$

=> $-3.29 < \mu_1 - \mu_2 < -0.70$

5 0

3 years ago

What multiplies to -9 and adds to 8

Free_Kalibri [48]

9 and -1 9*-1=-9 and 9-1=8

5 0

3 years ago