Please could someone help me with these questions sorry about the scribbling on one page I got stuck
1 answer:
Question 4
So the polygon has 10 sides, to calculate how much all the interior angles are summed up, you have to see how many triangles you can fit into the polygon (this works for any polygon), in this case it is 8 (see file attached). Therefore you do 8 x 180 = 1440, so the overall angle is 1440º. Now you do 1440 : 10, because there are 10 equal angles, and that is 144º.
Every angle has 144º
question 5
Bearings are always measured clockwise and you always start north. You are at point A and want to go to point B, how much do you have to turn (clockwise!!)?
345º
So the polygon has 10 sides, to calculate how much all the interior angles are summed up, you have to see how many triangles you can fit into the polygon (this works for any polygon), in this case it is 8 (see file attached). Therefore you do 8 x 180 = 1440, so the overall angle is 1440º. Now you do 1440 : 10, because there are 10 equal angles, and that is 144º.
Every angle has 144º
question 5
Bearings are always measured clockwise and you always start north. You are at point A and want to go to point B, how much do you have to turn (clockwise!!)?
345º
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Answer:
Option (2).
Step-by-step explanation:
Coordinates of points A(-2, 2), B(-1, -1), C(-1, 4) and (0, -2)
By using formula to get the length of any segment having extreme ends at and
,
d =
Length of segment AB =
= ≈ 3.16
Length of segment CD =
= ≈ 6.08
Length of CD ≈ 2(length of AB)
But length of horizontal segments are equal.
Therefore, function 'f' is vertically stretched to form 'g'.
g(x) = 2f(x)
Now 'f' is translated by 1 unit right,
g(x) = 2f(x - 1)
Option (2) will be the answer.
