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mote1985 [20]
3 years ago
13

If angle A is congruent to itself by the Reflexive property, which transformation could be used to prove triangle ABC is similar

to triangle ADE by AA similarity postulate?
A. Translate triangle ADE so that point D lies on point B to confirm angle D is congruent to angle B.


B. Translate triangle ADE so that point B lies on point E to confirm angle B is congruent to angle E.


C. Dilate triangle ABC from point A by the ratio segment AD over segment AB to confirm segment AD is similar to segment AB


D. Dilate triangle ABC from point A by the ratio segment AE over AC to confirm segment AE is similar to segment AC.
Mathematics
1 answer:
Umnica [9.8K]3 years ago
5 0

Answer:

A. Translate triangle ADE so that point D lies on point B to confirm angle D is congruent to angle B.

Step-by-step explanation:

Two triangles are said to be similar if the ratio of their corresponding sides are equal.

The AA Similarity Postulate states that If two angles of one triangle is congruent to two angles of another triangle, then the two triangles are similar.

Translation is the movement of a point up, down, left or right.

Since ∠A = ∠A (reflexive property of congruence)

We have to prove that ∠D = ∠B, by Translating triangle ADE so that point D lies on point B

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12345 [234]

Answer:

\frac{x^2}{784}+\frac{y^2}{400}=1

Step-by-step explanation:

<u><em>Horizontal Major Axis:</em></u>

   \frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}

<u><em>Vertical Major Axis:</em></u>

   \frac{(y-k)^2}{a^2}+\frac{(x-h)^2}{b^2}+

So these two expressions are essentially the same with the only difference being the location of "a" and "b". The length of the major axis will be "2a" and the length of the minor axis will be "2b". The way I remember this is because when you have the horizontal major axis the "a" value is in the denominator of the (x-h) and I think of "x" as a horizontal value, since it moves a point horizontally. When you have a vertical major axis the "a" value is in the denominator of (y-k) and I think of "x" as a vertical value, since it moves a point vertically.

So just by looking at the graph, you can easily determine that the eclipse has a horizontal major axis. This can be further proven, since the distance from the origin on the right side is 28, and the distance from the the top to the origin is only 20.

So you could set up an equation to solve for a, since 2a = length of major axis, but since we're given the two points, the "a" value is really just the length from the origin to the right/left side, and combining these together you get the value of 2a/major axis, but you don't have to do that. So by looking at the graph you'll see the distance from the origin to the right side is 28. This means "a=28"

You can do the same thing here for the "b" value, and since the top is 20 units away from the origin, "b = 20"

So now let's set up the equation:
\frac{x^2}{28^2} + \frac{y^2}{20^2}=1

Square the values in the denominator

\frac{x^2}{784}+\frac{y^2}{400}=1

5 0
2 years ago
Please answer this question i really need your help
navik [9.2K]
Functions:graph B,mapping A, Table B
Grape B is a function because it passes the vertical line test ( meaning when I draw a vertical line any where on the graph the line only touched one point),mapping A is a function because each x value has only one y value same with table.
Non function: graph A, mapping B, Table A
Graph A does not pass vertical line test so it is not a function, mapping B and Table A both have an x value that has two y values and that is not a function.
8 0
4 years ago
Can someone plz help me again :D
patriot [66]
For one boy it would be 4/5, but since its two boys, then it would be 4/5 for the first boy and 3/5 for the second because before any of the names are drawn, there are 4 boys names in the bag and 5 girls names. For the second boy, the would be 3 boys names and 5 girls names in the bag (assuming that the first name drawn was a boys).
5 0
4 years ago
PLEASE HELP!! Urgent! :((
PSYCHO15rus [73]

Answer:

the angle is 245°

Step-by-step explanation:

that is a pentagon, (a shape with 5 sides)

we know 4 of the angles in the pentagon

the sum of those 4 angles is

58°+100°+112°+25°=295°

to find a shapes total amount of °, the equation is (n-2)x180°

(5-2)x180°

=540°

540°-295°=245°

x=245°

6 0
3 years ago
Assume that you are on a cross-country flight at an altitude of 4,500 feet pressure altitude and your course is 275 degrees. The
lukranit [14]

First you need to find your True Air Speed (TAS). I used the formula:

TAS=IAS\sqrt{\frac{\rho_0}{\rho}}\\

where \rho_0 is the density at mean sea level at 15°C which is 1.225 kg/m^3 and \rho is the density of the air in which the airplane is flying. In this case with the given altitude and air temperature is about: 1.073 kg/m^3.

So TAS is equal to: 123 kt in this case.

To get the time of arrival you need to get your ground speed. For that you need to compensate for the wind speed and direction.  With the drift angle you can get your ground speed.

In this case you get ground speed of 115 kt which means to travel 218 nautical miles you need 1 h and 53 min which means you will arrive at: 1135.

6 0
4 years ago
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