Algebra factorize a4 - 3a2b2 + b4

Mathematics

1 answer:

Vesnalui [34]2 years ago

8 0

Answer:

The term a⁴-3a²b²+b⁴ can't be factorised

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Evaluate 5 + 6 · 2 – 8 ÷ 4 + 7 using the correct order of operations

Natali5045456 [20]

Do solve this you use PEMDAS. This stands for:
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Because there are no parentheses or exponents in this equation, we go straight to the division.

1) 8 divided by 4 equals two so we rewrite the equation. 5+6 x 2 - 2 + 7.

2) Next in order of pemdas is multiplication. Yes I know that in pemdas multiplication does come before division but it doesn’t matter in this problem which you do first. So now we do 6 x2 =12. We then rewrite the equation 5+12-2+7.

3) lastly, addition and subtraction are grouped together and you can just do it in order of the problem. So we do 5+12=17. 17-2=15. And 15+7=22.

So the final answer is: 22

8 0

2 years ago

Read 2 more answers

What is the amplitude, period, and phase shift of y= 5cos( x/2 + 2pi/3)

nordsb [41]

Y = A cos(Bx + C)
A - amplitude
$\frac{2\pi}{B}$ - period
$- \frac{C}{B}$ - phase shift

$y=5\cos{( \frac{x}{2} + \frac{2\pi}{3} )}
\\
\\y=5\cos{( \frac{1}{2}x + \frac{2\pi}{3})}
\\
\\A=5,B= \frac{1}{2},C= \frac{2\pi}{3}$

Amplitude: 5
Period: $\frac{2\pi}{B}=\frac{2\pi}{\frac{1}{2}}=4\pi$
Phase shift: $- \frac{C}{B} =- \frac{\frac{2\pi}{3}}{\frac{1}{2}}= -\frac{4\pi}{3}$