The equation of the plane that goes through these points is:
6x + 2y + z = 10.
<h3>How to find the equation of a plane given three points?</h3>
The equation of the plane is found replacing the points into the following equation:
ax + by + c = z.
For point A, we have that:
3b + c = 4.
For point B, we have that:
a + 2b + c = 0.
For point C, we have that:
-a + 6b + c = 4.
Hence the system is:
From the first equation, we have that:
c = 4 - 3b.
Replacing in the second, we have that:
a + 2b + 4 - 3b = 0
a - b = -4.
Replacing in the third, we have that:
-a + 6b + 4 - 3b = 4.
-a + 3b = 0.
a = 3b.
We have that a - b = -4, hence:
3b - b = -4
2b = -4
b = -2.
a = 3b, hence a = -6.
c = 4 - 3b -> c = 10.
Hence the equation is:
ax + by + c = z.
z = -6x - 2y + 10
6x + 2y + z = 10.
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Answer:
The equation is;
y = 12x-41
Step-by-step explanation:
Mathematically;
slope intercept form is;
y = mx + b
where m is slope and b is intercept
Since we already have the slope , the equation is;
y = 12x + b
To get b which is the y intercept, we simply substitute the value of the points given
Thus;
19 = 5(12) + b
19 = 60+ b
b = 19-60
b = -41
So the equation is;
y = 12x - 41
1) Expression 1: 16x^3 y
2) Expression 2: 24 xy^5
Procedure:
1) find the greatest common factor of the coefficients, 16 and 24:
16 = 2^4
24 = (2^3)*3
=> greatest common factor = 2^3 = 8
2) find the greatest common factor of x^3 y and xy^5
That is the common letters each raised to the lowest power:
=> xy
3) Then, the result is 8xy