Ten is mistakenly written by Tim in question.
Gabriel is making a mixture of compost and soil. In which he wants to mix 2 part compost to 10 parts potting soil. And he wants to end up with ten kilogram
It means compost is 2 pars out of 12 and potting soil is 10 parts out of 12
so, (2 / 12) x 10 kilogram of compost is used
= 1.66667 kilogram of compost Gabriel should use.
Answer:
<em>x is -34/3 and -26/3</em>
Step-by-step explanation:
Given the expression
3|1/2x+5| + 7 = 5
Removing the modulus sign
3(1/2x+5) + 7 = 5
Subtract 7 from both sides
3(1/2x+5) + 7 - 7= 5 - 7
3(1/2x+5) = -2
Open the bracket
3/2 x + 15 = -2
Subtract 15 from both sides
3/2 x + 15-15 = -2 - 15
3/2 x = -17
3x = -2*17
3x = -34
x = -34/3
<em>Hence the value of x is -34/3</em>
<em>For the negative function:</em>
3(1/2x+5) + 7 = 5
Subtract 7 from both sides
3(-(1/2x+5)) + 7 - 7= 5 - 7
3(-1/2x-5) = -2
Open the bracket
-3/2 x - 15 = -2
Add 15 from both sides
3/2 x + 15-15 = -2 + 15
-3/2 x = 13
-3x = 2 * 13
-3x =26
x = -26/3
<em>Hence the value of x is -26/3</em>
Answer:
Domain : {x | all real numbers} ; Range: {y | y > 0}
Step-by-step explanation:
The function can be written as :
![f(x)=\sqrt[\frac{2}{3}]{108^{2\cdot x}}\\\\\implies f(x)=(108)^{(\frac{3}{2})^{2\cdot x}}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B%5Cfrac%7B2%7D%7B3%7D%5D%7B108%5E%7B2%5Ccdot%20x%7D%7D%5C%5C%5C%5C%5Cimplies%20f%28x%29%3D%28108%29%5E%7B%28%5Cfrac%7B3%7D%7B2%7D%29%5E%7B2%5Ccdot%20x%7D%7D)
Now, since x is exponent so it can take any real values. So, its domain of f(x) is all real numbers
But value of f(x) can not be less than 1 because for x = 0 the value of f(x) is 1 and also for any values of x, the value of f(x) can never be less than 1
So, Range of f(x) is all real numbers greater than 0
Hence, Domain and Range of f(x) is given by :
Domain : {x | all real numbers} ;
Range: {y | y > 0}
