I do believe that those are called numbers
Pretty sure its 3.2.......
Answer:
Step-by-step explanation:
Answer:
$6,376.92
Step-by-step explanation:
-Let d be the rate of depreciation per year.
-Therefore, the value after n years can be expressed as:

#We substitute for the years 2009-2013 to solve for d:

#We then use the calculated depreciation rate above to solve for A after 10 yrs:

Hence, the value of the car after 10 yrs is $6,376.92
Step-by-step explanation:
applying the distance formula,
±√(0-5)^2 + (-3-0)^2 = ±√34 (rej -√34 since distance > 0)
Topic: coordinate geometry
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