8-2(6-4:2)
8-2(6-2)
8-2*4
8-8=0
Answer:
Step-by-step explanation:
Let f(x) be the polynomial function of minimum degree with real coefficients whose zeros are 5, -3, and -1 + 3i be f(x).
By the complex conjugate property of polynomials, -1-3i is also a root of this polynomial.
Therefore the polynomial in factored form is
We expand to get:
We expand further to get:\
Step-by-step explanation:
I tried. if I got this wrong I might need to go back to kindergarten
5 people running experiment i think but im not exactly sure