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Naily [24]
3 years ago
9

Use the rules of exponents to evaluate or simplify. Write without negative exponents.

Mathematics
1 answer:
koban [17]3 years ago
4 0

9514 1404 393

Answer:

  1

Step-by-step explanation:

Any non-zero number to the zero power is 1.

  3.4^0 = 1

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Allometric relations often can be modeled by ​f(x)= x^b​, where a and b are constants. One study showed that for a male fiddler
dolphi86 [110]

Answer:

a) f(2)= 0.448 (2)^{1.21}= 1.036 grams

b) 0.5 = 0.448 x^{1.21}

Dividing both sides by 0.448 we got:

\frac{0.5}{0.448} = x^{1.21}

We can appy the exponent \frac{1}{1.21} in both sides of the equation and we got:

(\frac{0.5}{0.448})^{\frac{1}{1.21}} = x= 1.095grams

Step-by-step explanation:

For this case we know the following function:

f(x) = 0.448 x^{1.21}

The notation is: x is the weight of the crab in​ grams, and the output​ f(x) is the weight of the claws in grams.

Part a

For this case we just need to replace x = 2 gram in the function and we got:

f(2)= 0.448 (2)^{1.21}= 1.036 grams

Part b

For this case we know tha value for f(x) =0.5 and we want to find the value of x who satisfy this condition:

0.5 = 0.448 x^{1.21}

Dividing both sides by 0.448 we got:

\frac{0.5}{0.448} = x^{1.21}

We can appy the exponent \frac{1}{1.21} in both sides of the equation and we got:

(\frac{0.5}{0.448})^{\frac{1}{1.21}} = x= 1.095grams

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3 years ago
Find the area of the figure. PLEASE HELP I NEED IT URGENT PLEASE
ale4655 [162]

Answer:

#5

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{ \rm{area = ( \frac{1}{2}  \times b_{b}  \times h_{b}) - ( \frac{1}{2} \times b_{s} \times h _{s} )}} \\  \\ { \tt{area = ( \frac{1}{2} \times 18 \times 7) - ( \frac{1}{2} \times (18 - 13) \times 7)  }} \\  \\ { \tt{area = (9 \times 7) - (2.5 \times 7)}} \\  \\ { \underline{ \tt{ \:  \: area = 45.5 \:  \: sq \: units \:  \: }}}

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Area = area of square + area of two right angled triangles

{ \tt{area = (s \times s) + 2( \frac{1}{2}  \times b \times h)}} \\  \\ { \tt{area = (6 \times 10) + (3 \times 5)}} \\  \\ { \underline{ \tt{ \:  \: area = 75 \:  \:  {m}^{2}  \:  \: }}}

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