Answer:
10 yes 18 no 17 no
Step-by-step explanation:
Hope this helps
Answer: a) yNA/100
b) NA(y-x)/100
c) (NA)/B
Step-by-step explanation:
a) The total amount of dollars owned by the shares' owner = N number of shares × A dollars per share = NA dollars
This total is then transferred to buy B shares which then appreciates by y%.
The amount of increase in portfolio from January to June = y% of total dollars invested = y% of NA dollars = yNA/100
b) If the shares were left with A, the increase in portfolio from January to June would be x% and = x% of the total Dollar amount = x% of NA dollars = xNA/100
How much more money made in that time would be the difference in interest, between taking the dollars to invest in share B or keeping the dollars on investment A
That is, (yNA/100) - (xNA/100) = NA(y-x)/100
c) Total dollars available after sale of the A stock = NA
Number of B stock this dollar can buy = Total dollars available/amount of B stock per share
That is, (NA)/B
QED!
Answer:
8 and a half hours
Step-by-step explanation:
Time arthur went to bed = 9:30 pm
Time arthur woke up = 6 am
Hours arthur was asleep = 24 - (9 and half + 6)
= 24 - 15 and a half
= 8 and a half
Answer:
(-3, 2)
Step-by-step explanation:
{3x=7y=5
{5x-2y=-19
solve....
maybe it was 3x + 7y = 5
and 5x - 2y = -19
2*(3x + 7y = 5)
7*(5x - 2y = -19)
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6x + 14y = 10
35x -14y = -133
41x = -123
x = -3
y = ...
5*(-3) - 2y = -19
-15 - 2y = -19
2y = 4
y = 2
(-3, 2)
