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3 years ago

7x + 8 + 3x2 - 5x + 9 Can someone show me how I would solve this equation? (Step by step please)

Mathematics

2 answers:

raketka [301]3 years ago

6 0

Answer:

3 x^2 + 2 x + 17

Step-by-step explanation:

hjlf3 years ago

6 0

Answer:

2x+23

Step-by-step explanation:

Simplify 3\times 23×2 to 66.

7x+8+6-5x+97x+8+6−5x+9

Collect like terms.

(7x-5x)+(8+6+9)(7x−5x)+(8+6+9)

Simplify.

2x+23

Done

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Solve for X x/7 = -8 Please help!!! Worth 20 points!!! I need an answer ASAP!!!

Vikentia [17]

Answer:

x = -56

Step-by-step explanation:

x/7 = -8

Multiply each side by 7

x/7 *7 = -8*7

x = -56

8 0

3 years ago

Given a function I and a subset A of its domain, let I(A) represent the range of lover the set A; that is, I(A) = {I(x) : x E A}

Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

$f(A) = \{x^2 \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2 \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4] = f(A \cap B)\\$

Therefore it is true for intersection. Now for union, we have that

$A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]$

Therefore, for this case, it would be true that $f(A\cup B) = f(A)\cup f(B)$ .

(b)

1 is not a set.

(c)

To begin with

$A\cap B \subset A,B$

Therefore

$g(A\cap B) \subset g(A) \cap g(B)$

Now, given an element of $g(A) \cap g(B)$ it will belong to both sets, therefore it also belongs to $g(A\cap B)$ , and you would have that

$g(A)\cap g(B) \subset g(A \cap B)$ , therefore $g(A)\cap g(B) = g(A \cap B)$ .

(d)

To begin with $A,B \subset A \cup B$ , therefore

$g(A) \cup g(b) \subset g(A\cup B)$

7 0

3 years ago

9/16 divided by 9 plz help thx for everyone that has helped me

Verizon [17]

0.5625 will be the answer to 9 divided by 16

3 0

2 years ago

D₁ vide using x² - 2x² 2× +3× -5 by ×-3 using synthetic division.

Vaselesa [24]

Answer:

Step-by-step explanation:

I think you are trying to use synthetic division for

$x^{4} -2x^{3} -2x^{2} +3x-5$ divided by x-3

First

x -3 = 0 , make it equal to 0 and add 3 to both sides

x = 3

Then we write all the coefficients and continue with

a pattern of multiply by 3 and add to the next coefficient.

See attachment.

5 0

1 year ago

How do you do this problem?? I'm very confused

Mamont248 [21]

You have to multiply by the complex conjugate so that you can clear the radical from the denominator. Once you do the multiplication simplify the radical. There's still a common factor in -54, -18, & 75 so divide all those by 3.

7 0

3 years ago