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alex41 [277]
3 years ago
14

A diamond ring increases in value at a rate of 5% per year. If the ring was purchased for $1200, which equation would calculate

how much will it be worth in 30 years?
Would it be

A - y = 1200(1+.05)^30

B - y = 30(1+.05)^1200

C - y = .05(1+1200)^30
Mathematics
1 answer:
Margarita [4]3 years ago
8 0

Answer:

A - y = 1200(1+.05)^30

Step-by-step explanation:

In this case, you need to calculate the future value and the formula to calculate that is:

FV=PV*(1+r)^n

FV=future value

PV=present value

r=rate

n=number of periods of time

The present value would be the price of the ring which is $1200. The rate is 5% per year and the number of periods of time is 30 years since you need to find the ring's worth in 30 years. Now, you can replace the values on the formula:

FV=1200*(1+0.05)^30

According to this, the answer is that the equation to calculate how much will it be worth in 30 years is: y = 1200(1+.05)^30.

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2 years ago
Of 100 students,65 are members of a mathematics club and 40 are members of a physics club. if 10 are members of neither club the
alexandr1967 [171]

a. 15 students are members of both clubs

b. 50 students only are members of the mathematics club

c. 25 students only are members of the physics club

Step-by-step explanation:

The given is:

  • There are 100 students
  • 65 are members of a mathematics club
  • 40 are members of a physics club
  • 10 are members of neither club

We need to find how many students are members of

a. both clubs?

b. only mathematics club

c. only physics club

∵ The total number of students = 100

∵ 10 are members of neither club

- Subtract 10 from 100 to find the members of the mathematics

  club or the physics club

∵ 100 - 10 = 90

∴ There are 90 members of the mathematics club or physics club

∴ n(mathematics or physics) = 90

∵ 65 students are members of a mathematics club

∵ n(mathematics) = 65

∵ 40 students are members of a physics club

∴ n(physics) = 40

∵ n(mathematics or physics) = n(mathematics) + n(physics) - n(both)

∴ 90 = 65 + 40 - n(both)

∴ 90 = 105 - n(both)

- Add n(both) to each side

∴ n(both) + 90 = 105

- Subtract 90 from each side

∴ n(both) = 15

∴ 15 students are members of both clubs

a. 15 students are members of both clubs

∵ 65 students are members of the mathematics club

∵ 15 of them are members of the physics club

∴ n(mathematics only) = 65 - 15 = 50

∴ 50 students only are members of the mathematics club

b. 50 students only are members of the mathematics club

∵ 40 students are members of the physics club

∵ 15 of them are members of the mathematics club

∴ n(physics only) = 40 - 15 = 25

∴ 25 students only are members of the physics club

c. 25 students only are members of the physics club

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