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PilotLPTM [1.2K]
3 years ago
11

Please Show Work.

Mathematics
2 answers:
nalin [4]3 years ago
6 0

Answer: x = 17

Step-by-step explanation:

Remember that supplementary angles add up to 180.

We also know that two angles create a straight line.

We have to find x in (5x-18)° and (4x + 45)°.

Now, we know that (5x-18) and (4x + 45) is 180.

Now, let's get started.

5x and 4x is equal to 9x.

Now, we have to combine the like terms.

9x + 27 = 153.

Subtract the number 153 from 180.

You get 17, so it is the answer.

Hope this helps!

s344n2d4d5 [400]3 years ago
5 0

Answer:

\huge\boxed{x=17}

Step-by-step explanation:

It's important to note that when two angles create a straight line, they are supplementary.

This means their angle measures add up to 180° since a 180° angle is a straight line.

Since we know the measures of both angles in equation form, we can add them together and have them equal 180 to solve for x.

(5x-18) + (4x+45) = 180

Combine like terms:

9x + 27 = 180

Subtract 27 from both sides:

9x = 153

Divide both sides by 9:

x = 17

So x = 17.

Hope this helped!

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Let E_1,E_2,E_3 are the events that denotes the good drive, medium drive and poor risk driver.

P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20

Let A be the event that denotes an accident.

P(A/E_1)=0.01

P(A/E_2=0.03

P(A/E_3)=0.10

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem,P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}

We have to find P(E_1/A)

Using the Bayes theorem

P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}

Substitute the values then we get

P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}

P(E_1/A)=0.0789

b.We have to find the probability Mr.Brophy is a medium driver

P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395

c.We have to find the probability Mr.Brophy is a poor driver

P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526

7 0
3 years ago
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