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3 years ago

Please Show Work.

Mathematics

2 answers:

nalin [4]3 years ago

6 0

Answer: x = 17

Step-by-step explanation:

Remember that supplementary angles add up to 180.

We also know that two angles create a straight line.

We have to find x in (5x-18)° and (4x + 45)°.

Now, we know that (5x-18) and (4x + 45) is 180.

Now, let's get started.

5x and 4x is equal to 9x.

Now, we have to combine the like terms.

9x + 27 = 153.

Subtract the number 153 from 180.

You get 17, so it is the answer.

Hope this helps!

s344n2d4d5 [400]3 years ago

5 0

Answer:

$\huge\boxed{x=17}$

Step-by-step explanation:

It's important to note that when two angles create a straight line, they are supplementary.

This means their angle measures add up to 180° since a 180° angle is a straight line.

Since we know the measures of both angles in equation form, we can add them together and have them equal 180 to solve for x.

$(5x-18) + (4x+45) = 180$

Combine like terms:

$9x + 27 = 180$

Subtract 27 from both sides:

$9x = 153$

Divide both sides by 9:

$x = 17$

So x = 17.

Hope this helped!

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Step-by-step explanation:

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jekas [21]

Answer:

The algorithm is given below.

#include <iostream>

#include <vector>

#include <utility>

#include <algorithm>

using namespace std;

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pair <long long, pair<int, int> > p[MAX];

void initialize()

{

for(int i = 0;i < MAX;++i)

id[i] = i;

}

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id[x] = id[id[x]];

x = id[x];

}

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void union1(int x, int y)

{

int p = root(x);

int q = root(y);

id[p] = id[q];

}

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{

int x, y;

long long cost, minimumCost = 0;

for(int i = 0;i < edges;++i)

{

// Selecting edges one by one in increasing order from the beginning

x = p[i].second.first;

y = p[i].second.second;

cost = p[i].first;

// Check if the selected edge is creating a cycle or not

if(root(x) != root(y))

{

minimumCost += cost;

union1(x, y);

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return minimumCost;

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int x, y;

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cin >> nodes >> edges;

for(int i = 0;i < edges;++i)

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cin >> x >> y >> weight;

p[i] = make_pair(weight, make_pair(x, y));

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// Sort the edges in the ascending order

sort(p, p + edges);

minimumCost = kruskal(p);

cout << minimumCost << endl;

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8 0

3 years ago

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mojhsa [17]

Answer:

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Step-by-step explanation:

Make sure your calculator is in degree mode.

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3 0

2 years ago

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Sindrei [870]

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Hope that helped =)

6 0

3 years ago