Answer:
Step-by-step explanation:
From the given information; Let's assume that R should represent the set of all possible outcomes generated from a bit string of length 10 .
So; as each place is fitted with either 0 or 1

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0
Now;
if a 0 bit and a 1 bit are equally likely
The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:
; 

Y = mx + b
m = -2, b = 4
<span>y = -2x + 4</span>
Answer:
y= - 3/4x + 13/2(8.5,0)(0,6.5)
rounded (9,0)(0,7)
Answer:

Step-by-step explanation:
In the fifth grade class,
of the girls have brown hair. Again among those of the brown-haired girls,
of them have long hair.
We are asked to find the fraction of the girls who have long brown hair in the class.
The fraction of the total students which have long brown hair will be (
) =
. (Answer)
Holy god gud luck on escaping that (*´ー`*)