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3 years ago

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Question 4 (1 point)

2 answers:

JulijaS [17]3 years ago

8 0

Answer:

c. the graph moves left 18 units

Step-by-step explanation:

edge 2021

(:

kirza4 [7]3 years ago

7 0

Answer:

left

Step-by-step explanation:

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The exponential function f(x) = 3(5)x grows by a factor of 25 between x = 1 and x = 3. What factor does it grow by between x = 5

Delvig [45]

Answer:

B) 25

Step-by-step explanation:

Given exponential function:

$f(x)=3(5)^x$

The growth factor between $x=1$ and $x=3$ is 25.

To find the growth factor between $x=5$ and $x=7$

Solution:

The growth factor of an exponential function in the interval $x=a$ and $x=b$ is given by :

$G=\frac{f(b)}{f(a)}$

We can check this by plugging in the given points.

The growth factor between $x=1$ and $x=3$ would be calculated as:

$G=\frac{f(3)}{f(1)}$

$f(3)=3(5)^3$

$f(1)=3(5)^1$

Plugging in values.

$G=\frac{3(5)^3}{3(5)^1}$

$G=\frac{(5)^3}{(5)^1}$ (On canceling the common terms)

$G=(5)^{(3-1)}$ (Using quotient property of exponents $\frac{a^b}{a^c}=a^{(b-c)}$ )

$G=(5)^{2}$

∴ $G=25$

Similarly the growth factor between $x=5$ and $x=7$ would be:

$G=\frac{f(7)}{f(5)}$

$f(7)=3(5)^7$

$f(5)=3(5)^5$

Plugging in values.

$G=\frac{3(5)^7}{3(5)^5}$

$G=\frac{(5)^7}{(5)^5}$ (On canceling the common terms)

$G=(5)^{(7-5)}$ (Using quotient property of exponents $\frac{a^b}{a^c}=a^{(b-c)}$ )

$G=(5)^{2}$

∴ $G=25$

Thus, the growth factor remains the same which is =25.

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Step-by-step explanation:

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Answer:

Either way, it gives us the prime factorization for 50 that is 5 x 5 x 2. The prime factorization of 50 can be expressed using exponents as 5^2 x 2.

Step-by-step explanation:

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"Raju's father age is 5 years more than three times of Raju's age. Raju's father age is 50 years."

Lana71 [14]

Let rajus age be x

His father=3x+5

ATQ

$\\ \bull\tt\longmapsto 3x+5=50$

$\\ \bull\tt\longmapsto 3x=50-5$

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$\\ \bull\tt\longmapsto x=\dfrac{45}{3}$

$\\ \bull\tt\longmapsto x=15$

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