What is the surface area of the composite figure? (Use 3.14 for π .)
1 answer:
The picture in the attached figure
we know that
surface area of the figure=[surface area of hemisphere]+[surface area of the cylinder]
step1
find the surface area of hemisphere
surface area hemisphere=2*pi*r²
for r=8 in
surface area hemisphere=2*pi*8²-----> 401.92 in²
step 2
find the surface area of the cylinder
surface area of cylinder=area of the base+perimeter of the base*height
area of the base=pi*r²
for r=8 in
area of the base=pi*8²----> 200.96 in²
perimeter of the base=2*pi*r----> 2*pi*8-----> 50.24 in
surface area of cylinder=200.96+50.24*7-----> 552.64 in²
step 3
surface area of the figure=[surface area of hemisphere]+[surface area of the cylinder]
surface area of the figure=[401.92]+[552.64]-----> 954.56 in²
the answer is
954.56 in²
we know that
surface area of the figure=[surface area of hemisphere]+[surface area of the cylinder]
step1
find the surface area of hemisphere
surface area hemisphere=2*pi*r²
for r=8 in
surface area hemisphere=2*pi*8²-----> 401.92 in²
step 2
find the surface area of the cylinder
surface area of cylinder=area of the base+perimeter of the base*height
area of the base=pi*r²
for r=8 in
area of the base=pi*8²----> 200.96 in²
perimeter of the base=2*pi*r----> 2*pi*8-----> 50.24 in
surface area of cylinder=200.96+50.24*7-----> 552.64 in²
step 3
surface area of the figure=[surface area of hemisphere]+[surface area of the cylinder]
surface area of the figure=[401.92]+[552.64]-----> 954.56 in²
the answer is
954.56 in²
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Answer:
Length of BH is 2 units.
Step-by-step explanation:
We have, ΔABC with ∠ABC = 90° and an altitude BH.
Also, it is given that the length of sides AH is 4 units and HC is 1 units.
Since, the 'Altitude Rule' states that 'the length of the altitude is the geometric mean of the line segments it bisects'.
So, we get that,
i.e.
i.e.
i.e.
Since, the length of the side cannot be negative.
So, length of BH is 2 units.