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lina2011 [118]
3 years ago
12

What is the surface area of the composite figure? (Use 3.14 for π .)

Mathematics
1 answer:
Sloan [31]3 years ago
5 0
The picture in the attached figure

we know that
surface area of the figure=[surface area of hemisphere]+[surface area of the cylinder]

step1
find the surface area of hemisphere
surface area hemisphere=2*pi*r²
for r=8 in
surface area hemisphere=2*pi*8²-----> 401.92 in²

step 2
find the surface area of the cylinder
surface area of cylinder=area of the base+perimeter of the base*height

area of the base=pi*r²
for r=8 in
area of the base=pi*8²----> 200.96 in²

perimeter of the base=2*pi*r----> 2*pi*8-----> 50.24 in

surface area of cylinder=200.96+50.24*7-----> 552.64 in²

step 3
surface area of the figure=[surface area of hemisphere]+[surface area of the cylinder]
surface area of the figure=[401.92]+[552.64]-----> 954.56 in²

the answer is
954.56 in²

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denis23 [38]

Answer:

3.5 YARD

Step-by-step explanation:

3.5 x 3= 10.5x12= 126

6 0
2 years ago
3 ^(1 − 7 x = 7 ^x find the exact value
Shalnov [3]

Answer:

x

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7

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7 0
3 years ago
Read 2 more answers
MEC makes a big family tent in the shape of a symmetrical triangular prism. The floor of the tent is 5 m long and 2.5 m wide. Th
SVEN [57.7K]

Answer:

15,236 sq in

Step-by-step explanation:

First, you have to split the net into three rectangles and two triangles

step 1

triangular base area

1/2 bh = 1/2 (44 in)(64 in)

= 1/2 (2,816 sq in)

= 1,408 sq in.

2 x 1,408 sq in = 2,816 sq in.

step 2

end rectangle area

lw = (68 in)(69 in)

= 4,692 sq in

2 x 4,692 sq in = 9,384 sq in

Now find the area of the middle rectangle

lw - (69 in) (44 in) = 3,039 sq in.

then add all the areas together

2,816 + 9,384 + 3,036 = 15,236 sq in

Hope this helps :)

3 0
3 years ago
What is the distance between the points (7, −10) and (−8, −10)?
marin [14]

Answer:

15

Step-by-step explanation:

Using the distance formula

7 0
3 years ago
Read 2 more answers
Find all the numbers for each shape
irina1246 [14]

Answer:

  • 1 = pentagon
  • 2 = diamond
  • 3 = square
  • 5 = circle
  • 6 = rectangle
  • 7 = oval
  • 8 = triangle
  • 9 = hexagon
  • 10 = trapezoid

Step-by-step explanation:

Each half of a hanger divides the total weight in half. The right-most vertical has a total weight of 80/16 = 5. It consists of a square and a diamond, and we know the square is 1 more than the diamond. That means 2 diamonds weigh 5 -1 = 4. A diamond weighs 2, and a square weighs 3. The other half of that balance is a circle, which weighs 5.

The total of a square and oval is 10, so the oval is 10 -3 = 7. The two trapezoids weigh 20, so each is 10.

The second vertical from the left is a circle and diamond which will weigh 5+2 = 7. That makes the sum of a pentagon and rectangle also be 7. The 7+7 = 14 below the square on the left branch makes the total of that branch be 14+3 = 17, which is also the sum of the triangle and hexagon.

The weight below the rectangle at top left is 17+17 = 34, and the weight of that entire branch is 40. Thus the rectangle is 40-34 = 6, which makes the pentagon 7-6 = 1.

We require the sum of the triangle and hexagon be 17, with the triangle being the smaller value, and both being 9 or less (the trapezoid is the only figure weighing more than 9). Hence the triangle is 8 and the hexagon is 9.

The weights are summarized in the answer section, above.

8 0
3 years ago
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