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3 years ago

Plsss helppp WILL GIVE BRAINLIEST

Mathematics

2 answers:

Ann [662]3 years ago

4 0

Answer:

I thinks it's point 2 and if it's wrong I am sorry for that

Ksju [112]3 years ago

3 0

2, Pls give me brainlyiest!!

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Which expression is equivalent to 5y+2y+6x+2y-x

____ [38]

♡Okie Dokie let's simplify Step-By-Step!♡
♡Here is the question you asked us:
5y+2y+6x+2y−x
5y+2y+6x+2y+−x

♡Combine Like Terms:
5y+2y+6x+2y+−x
(6x+−x)+(5y+2y+2y)

♡Your final answer is:
5x+9y

♡I hope this helps!♡

4 0

3 years ago

Read 2 more answers

Tacoma's population in 2000 was about 200 thousand, and has been growing by about 8% each year. If this continues, what will Tac

Anestetic [448]

Answer:

Tacoma's population in 2014 will be 587,439 people

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by the formula

$y=a(1+r)^x$

where

y is Tacoma's population in thousand

x is the number of years since 2000

r is the rate of change

a is the initial value

we have

$a=200\\r=8\%=8/100=0.08$

substitute

$y=200(1+0.08)^x$

$y=200(1.08)^x$

what will Tacoma's population be in 2014?

Find the value of x

$x=2014-2000=14\ years$

substitute the value of x

$y=200(1.08)^{14}=587.439\ thousand$

therefore

Tacoma's population in 2014 will be 587,439 people

5 0

3 years ago

135 apples are to be packed into boxes.each box can take only 12 apples.find the number of boxes that will be fully packed and t

jeka94

Answer:

11 boxes will be fully packed and .25 will be remaining

3 0

3 years ago

Read 2 more answers

Do anyone think this is right ?

mestny [16]

It is not true because there C and E are on different sides, if that makes sense (which means your answer is correct)

6 0

3 years ago

Read 2 more answers

Solve for x. −5(x−4)=−30 Enter your answer in the box.

saveliy_v [14]

First divide both sides by - 5,

$x - 4 = 6$

Move the constant to the right side of the equation and change its sign (-4 => +4)

$x = 6 + 4$

Add the numbers,

$x = 10$

~~
I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey

6 0

3 years ago