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Valentin [98]
2 years ago
10

Suppose that G(X) = F(x+ 9). Which statement best compares the graph of

Mathematics
1 answer:
podryga [215]2 years ago
6 0

Answer:

Suppose that G(X) = F(x+ 9). Which statement best compares the graph of

G(X) with the graph of F(x)?

O A. The graph of G(X) is the graph of F(x) shifted 9 units try the left.

B. The graph of G(x) is the graph of F(X) shifted 9 units down.

C. The graph of G(x) is the graph of F(x) shifted 9 units up.

D. The graph of G(X) is the graph of F(x) shifted 9 units to the right.

Step-by-step explanation:

Suppose that G(X) = F(x+ 9). Which statement best compares the graph of

G(X) with the graph of F(x)?

O A. The graph of G(X) is the graph of F(x) shifted 9 units try the left.

B. The graph of G(x) is the graph of F(X) shifted 9 units down.

C. The graph of G(x) is the graph of F(x) shifted 9 units up.

D. The graph of G(X) is the graph of F(x) shifted 9 units to the right.

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A student takes an exam containing 1414 multiple choice questions. The probability of choosing a correct answer by knowledgeable
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Answer:

0.0082 = 0.82% probability that he will pass

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 14, p = 0.3.

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{14,9}.(0.3)^{9}.(0.7)^{5} = 0.0066

P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014

P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002

P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024

P(X = 13) = C_{14,13}.(0.3)^{13}.(0.7)^{1} = 0.000002

P(X = 14) = C_{14,14}.(0.3)^{14}.(0.7)^{0} \cong 0

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.0066 + 0.0014 + 0.0002 + 0.000024 + 0.000002 = 0.0082

0.0082 = 0.82% probability that he will pass

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Kenya is solving the equation 5 3/4 - 1/6x = 4 1/2. She gets to 1 1/4 = 1/6x. Is this a valid way to solve the equation? answer
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Answer:

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Step-by-step explanation:

5 3/4 - 1/6x = 4 1/2

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divide both sides by 1/6, same thing as multiplying both sides by 6 (reciprocal)

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reduce: 15/2 = x

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