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slavikrds [6]
4 years ago
9

6 divided by 1/3 Use keep change flip

Mathematics
2 answers:
irga5000 [103]4 years ago
6 0
The answer is 18 because you keep 6/1 Chang division to multiplication then flip 1/3 to 3/1 then solve it which again the answer is 18 ;)
Andreyy894 years ago
4 0
Hello There!

\frac{6}{1} * \frac{3}{1} = \frac{18}{1}
= 18

Hope This Helps You!
Good Luck :) 

- Hannah ❤
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For a standard normal distribution (µ=0, σ=1), the area under the curve less than 1.25 is 0.894. What is the approximate percent
Nesterboy [21]

Answer:

10.6%

Step-by-step explanation:

Normal curves are symmetrical.  That means that on a standard normal distribution,  the area less than -1.25 is the same as the area greater than +1.25.  The total area under the curve is 1, so:

P = 1 - 0.894

P = 0.106

Approximately 10.6% of the area under the curve lies below -1.25.

8 0
4 years ago
Is 68 prime because i am doing homework and im stuck on this and it is very hard so help me please
BlackZzzverrR [31]

If  68  is a prime number, then the only factors it has are  1  and  68.
If it has any other factors besides  1  and  68, then it's NOT prime.

Right away, without any higher math, you can look at just the last digit
in 68 .  The last digit is '8'.  That tells you that '68' is an even number,
and THAT tells you that '2' must be one of its factors.  So '68' is not a
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The factors of  68  are  1,  2,  4,  17,  34, and  68 .    

68  has four more factors besides  1  and  68, so it's not a prime number.

8 0
3 years ago
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How many different 1-topping pizzas can be formed by choosing a size and topping if your choices for size are small, medium, lar
Rudik [331]
The answer is A. 28
4 0
3 years ago
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29/4 into mixed number
Rus_ich [418]
The answer would be 28 and 1/4. 
3 0
3 years ago
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two bags contains 10 balls each. Every round you choose with equal probability one of the two bags and pick out a ball. After a
Stells [14]

Answer:

6.10%

Step-by-step explanation:

For every round since we are choosing with equal probability, then the probability of choosing from either of the bags is 1/2

Here, this scenario is only possible when a particular bag has been chosen 10 times and the other bag has been chosen 6 times ( meaning a particular bag has been emptied and for a particular bag to be emptied, all of its content would have been picked)

Now on the 17th trial, an empty bag is chosen

Therefore the required probability will be;

16C0 * (1/2)^10 * (1/2)^6 * 1/2 = 0.0610 = 6.1%

4 0
4 years ago
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