Correct Answer:Option A. 0.01
Solution:This is a problem of statistics and uses the concept of normal distributions. We need to convert the score of 90 into z-score and then find the desired probability from standard normal distribution table.
Converting 90 to z-score:

Now we are to find the probability of z score being more than 2.33. From the z-table the probability comes out to be 0.01.
Therefore, we can conclude that the probability of class average is greater than 90 is 0.01.
If you turn the ratio 1:3 into a fraction it would be 1 over 3 I hope this helps
Answer:
135.5
Step-by-step explanation:
192-56.5= 135.5
Let the width = w.
The length is 6 times the width, so the length is 6w.
The perimeter is 70.
P = 2L + 2W
70 = 2(6w) + 2(w)
70 = 12w + 4w
70 = 14w
5 = w
The width is 5.
The length is 6 times the width, so the length is 6 * 5 = 30
Area of rectangle = LW
A = 5 * 30 = 150
Add the weight of both elephants then round to the nearest 100