Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60
t=1
Answer:
yes it is a function
Step-by-step explanation:
You have to take the numbers and see if any of them are the same in the X column if their are some of the same numbers you only write the number once. than you connect the numbers to the given output. If any numbers have 2 outputs it is not a function.
How to you write the number 5,000,000,000,000,000,000,000,000,000,000
tresset_1 [31]
The way you wrote it is how you write it unless you want to do scientific notation then the answer would be, 5x10^30 because for it to be in scientific notation it has to be between 10 and 1 so I moved the decimal spot over 30 to get it into scientific notation. Hope this helps out.
-7 is losing the fewest as it is the smallest number, and the number that is to the left of the number line.
