We are looking to find P(X>60 students)
X is normally distributed with mean 50 and standard deviation 5
We need to find the z-score of 60 students

To find the probability of P(Z>2), we can do 1 - P(Z<2)
So we read the probability when Z<2 which is 0.9772, then subtract from one we get 0.0228
The number of students that has score more than 60 is 0.0228 x 1000 = 228 students
The answer to this problem is 9 hopefully this helps you!
Answer:
W = 6t + 90
Step-by-step explanation:
Given :
Starting weight = intercept = 90 kg
Weight gained after 8 months = 138 kg
Using the slope intercept relation ;
We can obtain the rate of change, slope ;
y = mt + c
m = slope ; t = time after t months ; c = intercept
y = weight gained after 8 months
138 = 8m + 90
138 - 90 = 8m
48 = 8m
m = 48 / 8
m = 6
Hence, slope intercept equation equals :
W = 6t + 90
Answer:
x=-36
Step-by-step explanation:
Add the 7/2x +1/2x to be 8/2x which means that it'll be 4x=18=9/2
then subtract 9/2x on both sides so itll be

-9/2x -9/2x
because if you do 8/2-9/2 it's -1/2
then multiply the reciprocal to both sides so

which then cancels out -1/2 and makes it
x=-36