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Dmitriy789 [7]
3 years ago
12

Which is the value of this expression when p = 3 and q = negative 9? ((p Superscript negative 5 Baseline) (p Superscript negativ

e 4 Baseline) (q cubed)) Superscript 0 Negative one-third Negative StartFraction 1 Over 27 EndFraction StartFraction 1 Over 27 EndFraction One-third
Mathematics
2 answers:
Korvikt [17]3 years ago
8 0

Answer:

The answer is -1/27

Step-by-step explanation:

this is just the person above me's answer except it gets rid of the nonsense words.

pychu [463]3 years ago
7 0

Answer:

Negative StartFraction 1 Over 27 EndFraction

(-1/27)

Step-by-step explanation:

Given expression

(P^-5)(p^-4)(q^3)

When

P=3 and q=-9

(P^-5)(p^-4)(q^3)

=(3^-5)(3^-4)(-9^3)

=(1/3^5)(1/3^4)(-9^3)

=(1/243)(1/81)(-729)

Multiply all numerators

We have,

= (-729)/(243)(81)

Multiply all denominators

= -729/19,683

= -1/27

Negative StartFraction 1 Over 27 EndFraction

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Read 2 more answers
n engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such that
BartSMP [9]

Answer:

<em>The calculated t- value =  1.11 > 2.89 at 0.025 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>The engineer designed the valve such that it would produce a mean pressure is not equal to  5.4</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given mean of the Population (μ) = 5.4</em>

<em>Given sample size 'n' = 9</em>

<em>Mean of the sample (x⁻) = 5.7</em>

<em>Standard deviation of the sample (s) = 0.81</em>

<u><em>Step(ii):-</em></u>

<em>Null Hypothesis: H₀:</em>  The engineer designed the valve such that it would produce a mean pressure of 5.4

H₀: μ = 5.4

<em>Alternative Hypothesis : H₁:</em>  μ ≠ 5.4

Level of significance = 0.025

Test statistic

            t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }

           t = \frac{5.7 -5.4}{\frac{0.81}{\sqrt{9} } }

         t = 1.11

<em>Degrees of freedom </em>

<em>ν = n-1 = 9-1 =8</em>

t₀.₀₁₅ , ₈  = 2.89

<em>The calculated t- value =  1.11 > 2.89 at 0.025 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>The engineer designed the valve such that it would produce a mean pressure is not equal to  5.4</em>

<em></em>

<em />

7 0
3 years ago
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