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MrRissso [65]
2 years ago
13

At least two of its angles are right angles.

Mathematics
2 answers:
Vaselesa [24]2 years ago
4 0
Is their a picture that you’re referring to ?

If you’re asking how much do you need to make right angles it should be 90 degrees
Y_Kistochka [10]2 years ago
4 0

Answer:

True based on the conveniently provided picture

Step-by-step explanation:

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Plz do both plz plz plz
vlada-n [284]

Answer:

3. 18 meters.

4. A= 6. 25cm^2  and P= 10 cm

5. 16 feet and 3 feet.

Step-by-step explanation:

3. base= 2 (A/h)

2 (72/8) = 18

4. A= side^2

2.5^2 = 6.25

P= 4 sides

2.5 x 4= 10

5. 16x3= 48

6 0
3 years ago
Estimate and classify the critical points for the graph of the function<br> Please show work
ikadub [295]

The critical points of the function graphed are given as follows:

  • x = -1.5: Local maximum.
  • x = -1: Local minimum.

<h3>What are the critical points of a function?</h3>

The critical points of a function are the values of x for which:

f^{\prime}(x) = 0

In a graph, they are turning points, and are classified as follows:

  • Local maximum, if the functions changes from increasing to decreasing.
  • Local minimum, if the functions changes from decreasing to increasing.

Looking at the graph, the turning points are approximately:

  • x = -1.5: Local maximum.
  • x = -1: Local minimum.

More can be learned about critical points at brainly.com/question/2256078

#SPJ1

5 0
2 years ago
I need help for this, thanks
gulaghasi [49]

(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.

---------------------------------------------------------------------------------------

(b) The following functions are positive in quadrant III:

tangent, cotangent

The following functions are negative in quadrant III

cosine, sine, secant, cosecant

A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.

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3 years ago
How do you find the value of X? Isosceles and Equilateral Traingle
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Did they give values for the letters??
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ANTONII [103]

Answer:

I wish you a merry Christmas and happy holidays may the new years bring you something good!!!!!!!

Step-by-step explanation:

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