Question

PLEASE HELP,, MARKING BRAINLIEST!!! Given coordinates N(-1,-11) and P(-1,-3), find NP?

Answer 1

Given:

Two points are N(-1,-11) and P(-1,-3).

To find:

The value of NP.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Two points are N(-1,-11) and P(-1,-3). Using distance formula, we get

$D=\sqrt{(-1-(-1))^2+(-3-(-11))^2}$

$D=\sqrt{(-1+1)^2+(-3+11)^2}$

$D=\sqrt{(0)^2+(8)^2}$

On further simplification, we get

$D=\sqrt{0+64}$

$D=\sqrt{64}$

$D=8$

Therefore, the value of NP is 8 units.