Answer:
6
Step-by-step explanation:
replace x with 6 in the ecuation.
4(6)=24 - 8 =16
Answer: The solutions are not viable because the amount of the sale cannot be negative.
Step-by-step explanation:
The solution A = -5 is not viable because A represents the amount of sale in dollars and so cannot be a negative number. The minimum amount that a person can make from sales is $0 so anything less than that is not viable.
For instance, if you are selling shoes for $4 each and make no sales in the day, your sales would be $0. It is not possible that your sales would be -$4.
Answer:
89.1° or -1.4°
Step-by-step explanation:
1. Location:
You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.
The French troops are about 50 m below you and 1.2 km distant.
2. Finding the firing angle
Data:
R = 1200 m
u = 600 m/s
h = -50 m (the height of the target)
a = 9.8 m/s²
We have two conditions.
Horizontal distance
(1) 1200 = 600t cosθ
Vertical distance
(2) -50 = 600t sinθ - 4.9t²
Divide each side of (1) by 600cosθ.
![(3) \, t =\dfrac{2}{\cos \theta}](https://tex.z-dn.net/?f=%283%29%20%5C%2C%20t%20%3D%5Cdfrac%7B2%7D%7B%5Ccos%20%5Ctheta%7D)
Substitute (3) into (2)
![-50 = 600t \sin \theta - 4.9t^{2} = 600 \left( \dfrac{2}{\cos \theta} \right ) \sin \theta - 4.9 \left( \dfrac{2}{\cos \theta} \right )^{2}\\\\(4) \, -50 = 1200 \tan \theta - \dfrac{19.6}{\cos^{2} \theta}](https://tex.z-dn.net/?f=-50%20%3D%20600t%20%5Csin%20%5Ctheta%20-%204.9t%5E%7B2%7D%20%3D%20%20600%20%5Cleft%28%20%5Cdfrac%7B2%7D%7B%5Ccos%20%5Ctheta%7D%20%5Cright%20%29%20%5Csin%20%5Ctheta%20-%204.9%20%5Cleft%28%20%5Cdfrac%7B2%7D%7B%5Ccos%20%5Ctheta%7D%20%5Cright%20%29%5E%7B2%7D%5C%5C%5C%5C%284%29%20%5C%2C%20-50%20%3D%201200%20%5Ctan%20%5Ctheta%20-%20%5Cdfrac%7B19.6%7D%7B%5Ccos%5E%7B2%7D%20%5Ctheta%7D)
Recall that
(5) sec²θ = 1/cos²θ = tan²θ + 1
Substitute (5) into (4)
![-50 = 1200 \tan \theta - 19.6 \left(\tan^{2} \theta}+ 1\right )](https://tex.z-dn.net/?f=-50%20%3D%201200%20%5Ctan%20%5Ctheta%20-%2019.6%20%5Cleft%28%5Ctan%5E%7B2%7D%20%5Ctheta%7D%2B%201%5Cright%20%29)
Set up a quadratic equation
![\begin{array}{rcl}-50 & = & 1200 \tan \theta - 19.6\tan^{2} \theta -19.6 \\0 & = & 1200 \tan \theta - 19.6\tan^{2} \theta + 30.4\\0 & =&19.6\tan^{2} \theta - 1200 \tan \theta - 30.4\\0 & =&\tan^{2} \theta - 61.224 \tan \theta - 1.551\\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7D-50%20%26%20%3D%20%26%201200%20%5Ctan%20%5Ctheta%20-%2019.6%5Ctan%5E%7B2%7D%20%5Ctheta%20-19.6%20%5C%5C0%20%26%20%3D%20%26%201200%20%5Ctan%20%5Ctheta%20-%2019.6%5Ctan%5E%7B2%7D%20%5Ctheta%20%2B%2030.4%5C%5C0%20%26%20%3D%2619.6%5Ctan%5E%7B2%7D%20%5Ctheta%20-%201200%20%5Ctan%20%5Ctheta%20-%2030.4%5C%5C0%20%26%20%3D%26%5Ctan%5E%7B2%7D%20%5Ctheta%20-%2061.224%20%5Ctan%20%5Ctheta%20-%201.551%5C%5C%5Cend%7Barray%7D)
Solve for θ
Use the quadratic formula.
tanθ = 61.249 or -0.025
θ = arctan(61.249) = 89.1° or
θ = arctan(-0.025) = -1.4°
Answer: In the hundreds place.
Step-by-step explanation:
1. You know that the first number has a 7 in its tenths place. This means that it is after the decimal point. You can write is as following:
x.7
Where x represents the other digits.
2. The second number has a 7 with a value that is 1,000 times greater than the value of the 7 in the first number, this means that you can know the place of the 7 in the second number if you multiply the first number by 1,000, or in other words, move the decimal point three places to the rigth. Therefore:
x.7*1000=7xx
3. As you can see, the 7 is in the hundred place in the second number.
Answer:
Step-by-step explanation: