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3 years ago

Complete the following equation: a2 = b2 + c2 - ______.

Mathematics

1 answer:

Dima020 [189]3 years ago

8 0

Answer:

2 bc cos A

Step-by-step explanation:

Cosine rule

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Anybody know the answer

Karolina [17]

Answer:

5 (-9x)

Step-by-step explanation:

Product of 5

5 * ()

difference of 9

5 * (-9)

and a number

5 * (-9x)

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3 years ago

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Luis draws 1 card from a deck, 39 times. predict how many times he draws an ace.

anyanavicka [17]

He would draw 3 aces

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3 years ago

Label the following graph as vertical or horizontal:

vfiekz [6]

The answer is vertical.

8 0

3 years ago

Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx

shutvik [7]

$\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)$

Let $v=x+y$ , so that $\dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}$ :

$\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1$

Now the ODE is separable, and we have

$\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx$

Integrating both sides gives

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx$

For the integral on the left, rewrite the integrand as

$\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v$

Then

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C$

and so

$\csc v-\cot v=x+C$

$\csc(x+y)-\cot(x+y)=x+C$

Given that $y(0)=\dfrac\pi2$ , we find

$\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1$

so that the particular solution to this IVP is

$\csc(x+y)-\cot(x+y)=x+1$

5 0

3 years ago

Is 3/4 greater than 7/8?

yKpoI14uk [10]

3/4 = (2*3) / (2* 4) = 6/8

7/8.

Is 3/4 greater than 7/8?
Is like asking is 6/8 greater than 7/8? Because 3/4 is equivalent to 6/8.

The answer is No.

3 0

3 years ago

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