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sveta [45]
3 years ago
6

Help Me On These Please

Mathematics
1 answer:
RoseWind [281]3 years ago
7 0
#1 is true. The term they have in common is y with an invisible coefficient in-front of the second y term

#2 has zero like terms. 15 has no variable, and the other terms have different variables.

#3 has two like terms, that’s 9 and 8 which add to equal 17. The answer is 3x + 17 aka D.

#4 has two like terms, the numbers with the variable ‘n’. 4n + 7n = 11n. Your answer is 11n + 12 aka D
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Need help with questions 5 and 6
kirza4 [7]

Answer:


Step-by-step explanation:


7 0
3 years ago
Hii! please help asap. i’ll give brainliest
Harrizon [31]

Answer:

3 Miles

Step-by-step explanation:

The Median is the middle value of whatever data set, which means the median is 3 since its the middle value

5 0
2 years ago
The fence around a circular garden is 18 feet long. What is the area of the garden to the nearest square foot? Use 3.14 for pi.
Sidana [21]

Answer:

A = 26 ft²

Step-by-step explanation:

To find the area of a circle, use the formula A = πr²

We know π = 3.14 and C = 18.

Use the circumference to find "r". C = 2πr

C = 2πr

18 = 2(3.14)r

18 = 6.28r

r = 18/6.28        Exact answer

r ≈ 2.866           Rounded to three decimal places

You can use either of the two bolded "r" values. I will use the rounded answer in the formula for area.

Substitute π = 3.14 and r = 2.866.

A = πr²

A = (3.14)(2.866)²                  Solve exponents first

A = 3.14(8.213956)                Multiply

A = 25.7918218...                  Unrounded answer

A ≈ 26                                   Rounded to nearest square foot

Add the units back in.

<h3>A = 26 ft²</h3>
7 0
3 years ago
Write an equation that represents the line. (-3,-6) and (2,-2) use exact numbers
Ilia_Sergeevich [38]

Given:

The line passes through (-3,-6) and (2,-2).

To find:

The equation of line.

Solution:

If a line passes through two points (x_1,y_1)\text{ and }(x_2,y_2), then the equation of line is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

The line passes through (-3,-6) and (2,-2). So, the equation of line is

y-(-6)=\dfrac{-2-(-6)}{2-(-3)}(x-(-3))

y+6=\dfrac{-2+6}{2+3}(x+3)

y+6=\dfrac{4}{5}(x+3)

y+6=\dfrac{4}{5}(x)+\dfrac{4}{5}(3)

Subtract 6 from both sides.

y=\dfrac{4}{5}(x)+\dfrac{12}{5}-6

y=\dfrac{4}{5}(x)+\dfrac{12-30}{5}

y=\dfrac{4}{5}(x)+\dfrac{-18}{5}

y=\dfrac{4}{5}(x)-\dfrac{18}{5}

Therefore, the equation of line is y=\dfrac{4}{5}(x)-\dfrac{18}{5}.

3 0
3 years ago
Simplify t^12/t^6 help!
meriva

t^{12}/t^6=t^{12-6}=t^6

4 0
3 years ago
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