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3 years ago

Help Me On These Please

1 answer:

7 0

#1 is true. The term they have in common is y with an invisible coefficient in-front of the second y term

#2 has zero like terms. 15 has no variable, and the other terms have different variables.

#3 has two like terms, that’s 9 and 8 which add to equal 17. The answer is 3x + 17 aka D.

#4 has two like terms, the numbers with the variable ‘n’. 4n + 7n = 11n. Your answer is 11n + 12 aka D

You might be interested in

Subtract: 6a3 - 2a2 + 4 from 5a3 - 4a + 7

wlad13 [49]

subtract like terms

5a^3 - 6a^3 = -a^3

7 - 4 = 3

answer is -a^3 + 2a^2 - 4a + 3

8 0

3 years ago

Read 2 more answers

A rectangular sheep pen measures 5 meters long and 9 meters wide. The perimeter of the cow pen is double the perimeter of the sh

Tamiku [17]

35.99 mm
Hdfjivgbb hvvyhb

7 0

3 years ago

The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection = </em>

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$

5 0

3 years ago

Solve please I do not understand at all and please show work!

lina2011 [118]

So the recipe calls for 96 grams of sugar, and one cup is 128 grams of sugar.

She added a half of a cup, and as they said before one cup was 128 grams of sugar. So half of 128 is 64. So she added 64 grams of sugar. The recipe needs 96 grams so 64 grams is not enough sugar.

So 96 grams minus 64 equals 32 grams. So she still needs 32 grams of sugar.

So since the answers are all in cups, we must convert our answer from grams to cups.

So we have 32 grams of sugar left and to convert it we must put the 32 grams out of one cup. Once again one cup is 128 grams of sugar. So the amount of cups we need is 32/128 (fraction).

Also we need to simplify our fraction to completely answer the question. So we divide the numerator and denominator by 32.

So the final answer is 1/4. So the answer is D or the last answer out of the multiple choice.

8 0

3 years ago

Ten years ago, you purchased a $70,000, 5-year term life insurance policy. At that time you were 30 years old.

Darina [25.2K]

Answer:

a. 14,000

b. 140,000

Step-by-step explanation:

4 0

3 years ago