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Neko [114]
3 years ago
5

Perform the indicated operation and write in standard form 5i+(-9-i)

Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
6 0
5i+(-9-i)=\\
5i-9-i=\\
-9+4i
antoniya [11.8K]3 years ago
3 0
Since the sign before the parentheses is a + , we can just remove the parentheses.

<span>5i + (-9 - i) = 5i - 9 - i = -<u>9 + 4i</u></span>


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3 years ago
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Step-by-step explanation:

3 0
2 years ago
How to solve the equation
motikmotik
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5 0
3 years ago
1. Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial i
Katena32 [7]
Polynomial with real coefficients always has even number of complex roots. We know that one of them is 2 + 5i so the second one will be  2 - 5i and:

f(x)=\big(x-4\big)\big(x-(-8)\big)\big(x-(2+5i)\big)\big(x-(2-5i)\big)=\\\\=(x-4)(x+8)(x-2-5i)(x-2+5i)=\\\\=(x^2-4x+8x-32)(x^2-2x+5ix-2x+4-10i-5ix+10i-25i^2)\\\\=\big(x^2+4x-32\big)\big(x^2-4x+4-25\cdot(-1)\big)=\\\\=(x^2+4x-32)(x^2-4x+29)=\\\\=x^4-4x^3+29x^2+4x^3-16x^2+116x-32x^2+128x-928=\\\\=\boxed{x^4-19x^2+244x-928}

Answer B.
8 0
3 years ago
Read 2 more answers
Simplify 4( x - 6) ^2 / ( x - 6)​
Leno4ka [110]

Answer:

4x - 24

Step-by-step explanation:

\frac{4(x - 6 {)}^{2} }{(x - 6)}

4(x - 6) = 4x - 4 \times 6 = 4x - 24

4x - 24

5 0
2 years ago
Read 2 more answers
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