Ask question

Ask question

All categories

4 years ago

10

What is the approximate volume of a cone with a height of 12 in. and radius of 9 in.? Use 3.14 to approximate pi, and express yo

ur final answer to the nearest hundredth. brainly

1 answer:

butalik [34]4 years ago

7 0

The answer to this is 1017.36

You might be interested in

Beinggreat78 please answer

exis [7]

$\boxed{\sf A.~530.66}\boxed$

________

$\sf Solve$

$\sf Given~diameter~is~26~centimeters$

$\sf Use~diameter-to-area~formula$

$\sf Formula:$ $\frac{1}{4} \pi d^2 = \frac{1}{4} * \pi * [diameter]^2$

________

$\sf Solve(Equation/Result)$

$\frac{1}{4} * \pi * d(26)^2 = 530.66~cm^2$

3 0

2 years ago

Should the minimum wage be increased?

MatroZZZ [7]

Answer:

The best answer is C

Step-by-step explanation:

A is not correct because the total amount of people that participated is 300

B is no correct because the 75% would be more than 20

C is correct because 20% of 100 is 20

D is wrong because A has more people supporting raising it.

correct me if I am wrong.

8 0

3 years ago

Read 2 more answers

Carly works less than 20 hours per week helping her grandfather on his farm.

horrorfan [7]

Answer:

h>20

Step-by-step explanation:

I'm not sure though

3 0

3 years ago

Bonnie is making a dipping sauce. She mixes 150 milliliters of soy sauce with 100 milliliters of vinegar. How much soy sauce doe

natali 33 [55]

First step

You must stablish a relation

150 ml sauce/100 ml vinegar

If 100 ml vinegar_______150ml sauce then 11 ml vinegar ____x ml sauce

Second step

You must resolve x from the equation

X= (11ml vinegar*150 ml soya)/(100 ml vinegar)= 16.5 ml sauce, it means that it will be 16,5 ml sauce by every 11 ml of vinegar

5 0

4 years ago

Read 2 more answers

Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. Y = (4/9) x

frez [133]

Answer:

V = 8.06 cubed units

Step-by-step explanation:

You have the following curves:

$y_1=\frac{4}{9}x^2=f(x)\\\\y_2=\frac{13}{9}-x^2=g(x)$

In order to calculate the solid of revolution bounded by the previous curves and the x axis, you use the following formula:

$V=\pi \int_a^b [(g(x))^2-(f(x))^2]dx$ (1)

To determine the limits of the integral you equal both curves f=g and solve for x:

$f(x)=g(x)\\\\\frac{4}{9}x^2=\frac{13}{9}-x^2\\\\\frac{4}{9}x^2+x^2=\frac{13}{9}\\\\\frac{13}{9}x^2=\frac{13}{9}\\\\x=\pm 1$

Then, the limits are a = -1 and b = 1

You replace f(x), g(x), a and b in the equation (1):

$V=\pi \int_{-1}^{1}[(\frac{13}{9}-x^2)^2-(\frac{4}{9}x^2)^2]dx\\\\V=\pi \int_{-1}^1[\frac{169}{81}-\frac{26}{9}x^2+x^4-\frac{16}{81}x^4]dx\\\\V=\pi \int_{-1}^1 [\frac{169}{81}-\frac{26}{9}x^2+\frac{65}{81}x^4]dx\\\\V=\pi [\frac{169}{81}x-\frac{26}{27}x^3+\frac{65}{405}x^5]_{-1}^1\\\\V\approx8.06\ cubed\ units$

The volume of the solid of revolution is approximately 8.06 cubed units

8 0

3 years ago