2x + 5y + 7x
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Combine like terms
(2x + 7x)
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9x + 5y
Let's write an inequality, such as follows: x < sqrt(50) < y. Square both sides of the equation. We get x^2 < 50 < y^2. Obviously, x is between 7 and 8. Also notice, that for integers a,b, (ab)^2/b^2, equals a^2. So let's try values, like 7.1. Using the previous fact, (7.1)^2, equals (71)^2/100. So, (7.1)^2, equals 50.41. Thus, our number is between 7 and 7.1. We find, with a bit of experimentation, that the square root of 50, is 7.07.
Answer:
5
Step-by-step explanation:
they are equal to one another soo make an equation and solve it 2x-10 then divide that and get 5
Answer:
19/7
Step-by-step explanation:
The additive inverse of 7/19=1 : 7/19= 19/7
Answer:
same here, i cant figure it out.
Step-by-step explanation:
