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Komok [63]
3 years ago
11

Jared wants a quick trip by bus or train to New York. The bus’s average speed is shown in the graph. The train’s average speed i

s shown in the table. Which form of transportation travels a greater distance per hour?
Mathematics
2 answers:
Elis [28]3 years ago
5 0

Answer:

The bus travels 15 miles more per hour than the train.

TTM ;)

masha68 [24]3 years ago
3 0

The bus travels 15 miles more per hour than the train.

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PLS HELP WILL IVE BRAINLIST
pashok25 [27]

Answer:

inches: 0 and 7

Step-by-step explanation:

because you are subtracting by 1

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3 years ago
A one-parameter family of solutions of the de p' = p(1 − p) is given below.
tensa zangetsu [6.8K]

Answer:

A solution curve pass through the point (0,4) when c_{1} = -\frac{4}{3}.

There is not a solution curve passing through the point(0,1).

Step-by-step explanation:

We have the following solution:

P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}

Does any solution curve pass through the point (0, 4)?

We have to see if P = 4 when t = 0.

P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}

4 = \frac{c_{1}}{1 + c_{1}}

4 + 4c_{1} = c_{1}

c_{1} = -\frac{4}{3}

A solution curve pass through the point (0,4) when c_{1} = -\frac{4}{3}.

Through the point (0, 1)?

Same thing as above

P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}

1 = \frac{c_{1}}{1 + c_{1}}

1 + c_{1} = c_{1}

0c_{1} = 1

No solution.

So there is not a solution curve passing through the point(0,1).

3 0
3 years ago
What’s the midpoint of the line segment joining A and B<br><br> A(2,-5);B(6,1)
IRISSAK [1]

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{2}~,~\stackrel{y_1}{-5})\qquad B(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{6+2}{2}~~,~~\cfrac{1-5}{2} \right)\implies \left( \cfrac{8}{4}~,~\cfrac{-4}{2} \right)\implies (4,-2)

7 0
2 years ago
The strength of a cable is proportional to the square of its diameter. If a 2-cm cable will support 800kg, how much will a 3-cm
xz_007 [3.2K]
Strength [is proportional to] d^2
strength1/(d1)^2 = strength2/(d2)^2
800kg/(2cm)^2 = strength2/(3cm)^2
strength2 = 800 kg * (3 cm)^2/(2 cm)^2
strength2 = 800 kg * 3^2/2^2
strength2 = 800 kg * 9/4
strength2 = 1800 kg
3 0
3 years ago
The radius of the base of a cylinder is 27 cm and it’s height is 33cm. Find the surface area of the cylinder in terms of pi.
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Answer:

10178.76

Step-by-step explanation:

use formula:-2πrh+2πr^2

6 0
3 years ago
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