For three fair six-sided dice, the possible sum of the faces rolled can be any digit from 3 to 18.
For instance the minimum sum occurs when all three dices shows 1 (i.e. 1 + 1 + 1 = 3) and the maximum sum occurs when all three dces shows 6 (i.e. 6 + 6 + 6 = 18).
Thus, there are 16 possible sums when three six-sided dice are rolled.
Therefore, from the pigeonhole principle, <span>the minimum number of times you must throw three fair six-sided dice to ensure that the same sum is rolled twice is 16 + 1 = 17 times.
The pigeonhole principle states that </span><span>if n items are put into m containers, with n > m > 0, then at least one container must contain more than one item.
That is for our case, given that there are 16 possible sums when three six-sided dice is rolled, for there to be two same sums, the number of sums will be greater than 16 and the minimum number greater than 16 is 17.
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Answer:
90/13, 45/13
Step-by-step explanation:
Simplify:
5y+2x-3=0
5y=-2x+3
y=-2/5 x+3
Sope intercept of the line is y=-2/5 x+ 3/5.
The intercept is 3/5.
Check: x=0 when y=3/5
5y+2x-3=0
5(3/5)+2x-3
3+2x-3=0
2x=0
x=0
Correct
The answer is 3/5.
Answer:
$540
Step-by-step explanation:
1 member 1 day :$480/80/20 = $3
12 members 15 day = $3 * 12 * 15 = $540
Hope this helps!!!
Answer:
numbers that are plotted on a graph
Step-by-step explanation:
examples:
(2,8) this is a coordinate
(4,16)
(5,25)
